Recent content by justsomebody

  1. J

    Projectile motion question and minimum initial speed

    o ok now i just need to redo part a and b can't find height without these 2 anyway lol im off to bed cya =D and i really appreciate you taking time out to help me =D sometimes too much just isn't enough coz i really need time to digest all this
  2. J

    Projectile motion question and minimum initial speed

    its ok ill try to clear my mind and do it at a later time thank you so much for all your help =D
  3. J

    Projectile motion question and minimum initial speed

    lol I am sorry for taking up your time =o but with the equation s = 1/2at^2, as u = 0. s = 1/2(9.8)(3.91)^2 which = 74.91169 ~ 75m o_O im still guessing the t should be divided by 2 den max h = 75/2 = 37.5 =O =o nvm u mentioned halfway across =D is it correct =D
  4. J

    Projectile motion question and minimum initial speed

    first equation => s = ut (horizontal) second equation => s = ut + 1/2at^2 ( vertical ) s = 1/2at^2? =o but i still need to find t 1st =o man I am confused now i dun even know how to find t =o
  5. J

    Projectile motion question and minimum initial speed

    lol now I am stuck again is it zero? i can't do it =o i only used 37.5 * tan45 lol = 37.5 oo how do u find maximum height lol
  6. J

    Projectile motion question and minimum initial speed

    i guess 37.5m =o both the height and half-width
  7. J

    Projectile motion question and minimum initial speed

    =o ic but is it possible to assume the maximum height to be at half of the river's width? =o
  8. J

    Projectile motion question and minimum initial speed

    =O u remembered thx for the help again =D Assuming angle to be 45 degrees, maximum height i tink is => tan45 = h / 75 h = 75m s = ut + 1/2at^2 t = sqrt(75/4.9) = 3.912303982 = 3.91s which answered part b but is there anyway to get part a 1st before part b =O mayb there is a way now with the...
  9. J

    Projectile motion question and minimum initial speed

    Homework Statement Assume acceleration due to gravity is 9.8ms^-2 It has been said that in his youth George Washington threw a silver dollar across a river. Assuming that the river was 75m wide, (a) what minimum initial speed was necessary to get the coin across the river (b) how long was...
  10. J

    Physics Homework: Calculate Velocity & Direction of Beer Mug

    is the velocity in Y-direction => v^2 = u^2 + 2as => v = sqrt(2as) => v = sqrt(2*9.8*0.86) => v = 4.105605924 => v = 4.11m/s how do u find the angle =o i can only think of tan(teetle) = vertical v / horizontal v which is wrong nvm i forgot to do 360-teetle lol =D thanks everyone for helping...
  11. J

    Physics Homework: Calculate Velocity & Direction of Beer Mug

    the next part really stumps me =o how do you calculate rotation angle does it have something to do with projectile motion thing ill go try out
  12. J

    Physics Homework: Calculate Velocity & Direction of Beer Mug

    lol thanks for the all help appreciate it =D i got the answer i guess => s = ut + 1/2at^2 ( vertical distance ) => u = 0, sqrt(2s/a) = t => t = 0.41893938 => s = 1/2(u+v)t ( horizontal distance ) => 1.4 = 1/2(u + v) t where v = u => 1.4/t = 1/2 * 2u => u = 3.341772263
  13. J

    Physics Homework: Calculate Velocity & Direction of Beer Mug

    Homework Statement Assume gravitational force is 9.8 ms^-2 In a local bar, a customer slides an empty beer mug on the counter for a refill. The bartender is momentarily distracted and does not see the mug, which slides off the counter and strikes the floor 1.4 m from the base of the...
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