o ok now i just need to redo part a and b can't find height without these 2 anyway lol
im off to bed cya =D and i really appreciate you taking time out to help me =D sometimes too much just isn't enough coz i really need time to digest all this
lol I am sorry for taking up your time =o
but with the equation s = 1/2at^2, as u = 0.
s = 1/2(9.8)(3.91)^2 which = 74.91169 ~ 75m o_O
im still guessing the t should be divided by 2
den max h = 75/2 = 37.5 =O
=o nvm u mentioned halfway across =D
is it correct =D
first equation => s = ut (horizontal)
second equation => s = ut + 1/2at^2 ( vertical )
s = 1/2at^2? =o
but i still need to find t 1st =o
man I am confused now i dun even know how to find t =o
=O u remembered
thx for the help again =D
Assuming angle to be 45 degrees,
maximum height i tink is => tan45 = h / 75
h = 75m
s = ut + 1/2at^2
t = sqrt(75/4.9)
= 3.912303982
= 3.91s which answered part b
but is there anyway to get part a 1st before part b =O
mayb there is a way now with the...
Homework Statement
Assume acceleration due to gravity is 9.8ms^-2
It has been said that in his youth George Washington threw a silver dollar
across a river. Assuming that the river was 75m wide,
(a) what minimum initial speed was necessary to get the coin across the river
(b) how long was...
is the velocity in Y-direction
=> v^2 = u^2 + 2as
=> v = sqrt(2as)
=> v = sqrt(2*9.8*0.86)
=> v = 4.105605924
=> v = 4.11m/s
how do u find the angle =o
i can only think of tan(teetle) = vertical v / horizontal v which is wrong
nvm i forgot to do 360-teetle lol =D
thanks everyone for helping...
lol thanks for the all help appreciate it =D i got the answer i guess
=> s = ut + 1/2at^2 ( vertical distance )
=> u = 0, sqrt(2s/a) = t
=> t = 0.41893938
=> s = 1/2(u+v)t ( horizontal distance )
=> 1.4 = 1/2(u + v) t where v = u
=> 1.4/t = 1/2 * 2u
=> u = 3.341772263
Homework Statement
Assume gravitational force is 9.8 ms^-2
In a local bar, a customer slides an empty beer mug on the counter for a refill.
The bartender is momentarily distracted and does not see the mug, which
slides off the counter and strikes the floor 1.4 m from the base of the...