Physics Homework: Calculate Velocity & Direction of Beer Mug

AI Thread Summary
The discussion revolves around calculating the velocity and direction of a beer mug that slides off a bar counter. The mug slides off a height of 0.86 m and lands 1.4 m away from the base, with gravitational acceleration assumed at 9.8 m/s². The initial velocity of the mug is calculated to be approximately 3.34 m/s horizontally, while the vertical velocity just before impact is about 4.11 m/s. Participants suggest breaking the problem into horizontal and vertical components to simplify calculations, and the angle of impact is derived using trigonometric relationships. The thread concludes with users expressing gratitude for the assistance in solving the physics problem.
justsomebody
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Homework Statement


Assume gravitational force is 9.8 ms^-2

In a local bar, a customer slides an empty beer mug on the counter for a refill.
The bartender is momentarily distracted and does not see the mug, which
slides off the counter and strikes the floor 1.4 m from the base of the counter.
If the height of the counter is 0.86 m,

(a) with what velocity did the mug leave the counter, and
(b) what was the direction of the mug’s velocity just before it hit floor?

2. The attempt at a solution

Don't really understand the question at all =d can any1 help =D

Ans (a) 3.34 m/s at 0° (b) 309°
 
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justsomebody said:

Homework Statement


Assume gravitational force is 9.8 ms^-2

In a local bar, a customer slides an empty beer mug on the counter for a refill.
The bartender is momentarily distracted and does not see the mug, which
slides off the counter and strikes the floor 1.4 m from the base of the counter.
If the height of the counter is 0.86 m,

(a) with what velocity did the mug leave the counter, and
(b) what was the direction of the mug’s velocity just before it hit floor?

2. The attempt at a solution

Don't really understand the question at all =d can any1 help =D

Ans (a) 3.34 m/s at 0° (b) 309°

Try determining the time that it takes for an object to fall from .86m.
 
the first thing u should do when doing a problem like this is split it up into a problem in the x (horizontal)direction, and one in the y (vertical)direction. Try to view it as two separate problems but with one common factor that will always stay the same between the two problems. Split up different distances, acceleration, and different velocities and other relevant information. Once done with that you might have some more insight on how the problem is handled.
 
lol thanks for the all help appreciate it =D i got the answer i guess
=> s = ut + 1/2at^2 ( vertical distance )
=> u = 0, sqrt(2s/a) = t
=> t = 0.41893938

=> s = 1/2(u+v)t ( horizontal distance )
=> 1.4 = 1/2(u + v) t where v = u
=> 1.4/t = 1/2 * 2u
=> u = 3.341772263
 
Last edited:
the next part really stumps me =o
how do you calculate rotation angle
does it have something to do with projectile motion thing
ill go try out
 
justsomebody said:
the next part really stumps me =o
how do you calculate rotation angle
does it have something to do with projectile motion thing
ill go try out

You know the velocity of the glass in the X-direction. If you can determine the velocity in the Y-direction at impact, you can determine the angle.
 
Borg said:
You know the velocity of the glass in the X-direction. If you can determine the velocity in the Y-direction at impact, you can determine the angle.

is the velocity in Y-direction
=> v^2 = u^2 + 2as
=> v = sqrt(2as)
=> v = sqrt(2*9.8*0.86)
=> v = 4.105605924
=> v = 4.11m/s

how do u find the angle =o

i can only think of tan(teetle) = vertical v / horizontal v which is wrong
nvm i forgot to do 360-teetle lol =D
thanks everyone for helping me to solve this question =D
 

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