Response part 2 - I'm still drawing a blank for R^2. I don't think I know the complex form of impedance. I know that in a parallel circuit Z^-1 = 1/Z+1/Z+1/Z+...but trying to do that in terms of R, C, and L got really messy and the result didn't give me any "ah-ha" moments.
Ok, so I initially tried to work the result backwards. R^2 = L/C is the same as R^2 = L*1/C, this formula is independent of frequency, so I added frequency back in.
w/w*L*1/C. Which gives wL*1/wC. and then wL = XL and 1/wC = XC. Therefore R^2 = XL/XC. The only way I could get ohms = ohms...
Homework Statement
You have a circuit supplied with AC voltage, it has 2 parallel branches, 1 with R and L, the other with R and C.
a) If (frequency) w^2 = 1/LC, prove that the power in each branch is equal.
b) If R^2 = L/C, show that the power is the circuit is independent of frequency...