Recent content by jwatts

I don't know if this was already brought up so here it goes. In the problem you send out two probes away from the black hole (orthogonally I guess). The first one is sent out before crossing the horizon, the second one is sent out after. The "observation" is then that the second probe is moving...

The graph isn't actually labeled as the chi-squared distribution. It's merely saying it's a variation of the chi-squared distribution. The density function given on the second page is correct. Chi-squared is just a gamma distribution so it's obvious the first page doesn't show a standard...

ok so the sum goes a bit like this k!(1+ (k+1)+((k+2)(k+1)/2)+((k+1)(k+2)(k+3)/3)+...)

n choose k = n!/k!(n-k)! it's called the binomial coefficient saying it's k!*(n choose k) is kind of redundant but it let's you look at it in a different way same way as looking at it like a gamma, even though gamma is used for continuous situations normally

false P(X=k) for any density function is 0. The probability density function tells you the probability that the experiment ends up in some interval. For instance, the PDF will tell you how likely it is that you find someone between 5 feet and 6 feet, if you use the normal curve perhaps. It...

if you have a gambling problem, you should fold

if it helps it's the sum of k! * i choose k or you could break it down into gamma(i+1)/(gamma(i-k+1)

No thanks.

From what I know coordinate free systems exist in and of themselves. For instance to find the volume of a cube you need only find the length of a side and v=s^3. The Cartesian, cylindrical, spherical, etc need not be used. Though every coordinate system can be used to derive the formula for the...

now let's say all the probabilities aren't necessarily the same

How close could a tachyon get to a black hole and still escape?

Long story short I'm looking for an answer in the form of an equation of two variables, f(λ,n) where n is the number of settings and λ is the total value. This equation should output the probability needed.

One, I don't think this is the right section for your question. Unless you mean you expect to only check 3 times I don't think that is right. Let's say I check one and it's fine, the second one I check is defective and the third one I check is defective. I would need one more test to see...

I'm not big on number theory and I know others will post after me with much more knowledge but I will start it off by what makes sense to me. The definition, as you say, is that it can be mapped onto ℝ with a one to one correspondence. If it can we call it countable. Don't mess this up with...

micromass has the right answer. The average number of rolls will be 6. Your experiment is perfectly described by a geometric random variable. It says the probability (in this case) of rolling a 6 in σ rolls is ((1-(1/6))^σ-1)(1/6). As you can see, as you increase the number of times tried the...