Should you call in this situation? (Hold'em card game)

  • Thread starter Thread starter thetaobums
  • Start date Start date
  • Tags Tags
    Game
AI Thread Summary
In a late position in a 1/2 NL Hold'em cash game with pocket jacks, a player faces a decision after a loose passive player bets $12 and a tight player goes all in for $75. The player must consider the pot odds, needing to risk $100 more to call the original bettor's all-in of $175. With a pot odds ratio of 1.33 to 1, which is less than two to one, calling is mathematically justified, especially with a significant chip lead. The decision should focus on the current pot size and the players' likely hands rather than the amount already invested. Ultimately, the analysis suggests that calling is the optimal play in this scenario.
thetaobums
Messages
13
Reaction score
0
You are in late position with $400 at a 1/2 NL Hold'em cash game with pocket jacks. The player under the gun (a loose passive player) bets out $12. Two players fold, then a very tight (all in or nothing) player in middle position goes all in for $75. Two more players fold. You call his $75. The remaining players fold to the original better who goes all in for $175 total. Mathematically, should you call him as well or should you fold?
 
Last edited:
Physics news on Phys.org


if you have a gambling problem, you should fold
 
  • Like
Likes 1 person
probably call

You need to risk $100 more to call. You already have put in $75. 100/75 is 1.33, less than two to one. As long as it's less than two to one and you have a big chip lead, you should call.
 
There's no reason how much you've put in should matter. All that matters is how much money is currently in the pot, how much each of you has on the table, and your beliefs about the other players' cards.
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...
Back
Top