Recent content by Kaevan807

Finally got a chance to meet up with my lecturer today, who said that Max deceleration occurs when the front brake only is applied and the back wheel just comes off the ground, i.e. The equation that I have at the start. Didn't realize that it tipped about the bottom of the front wheel which...

Sorry, still very confused.. First off, why are we calculating Torque? Torque is a measure of how much a force causes an object to rotate right? So it makes more sense to calculate Torque than moments? Where are we taking the Torque about? The object will rotate about the axle of the...

But if α = 0, then surely τ = 0? Which tells me what? Is there some equation that all of that goes into? Really don't get where I'm supposed to be going with this question

Just getting more and more confused :P I understand tipping occurs when Nrear = 0, but what is T in that equation? I is the moment of inertia right? But how do I calculate the moment of inertia of a bicycle? (Moments of inertia really aren't my strong point) And how do I calculate the...

By tipping I presume you mean over the handlebars rather than to the side? How do I calculate the maximum deceleration without ignoring tipping then?

So does that mean I was right and that the maximum deceleration will be μ*g? Or did I just completely misread what you just said?

Homework Statement I'm only trying to answer the maximum deceleration possible question, not the rest. Homework Equations Not really sure which equations are applicable, I know the Maximum deceleration of a body in general will be a = μ*g. Although I would think that moments...

Homework Statement In the badly loaded front-wheel-drive minibus shown in Figure Q26 the centre of gravity has been moved away from the driving wheels, determine the max acceleration possible in m/s2 if l=3.0 m, h=1 m, and the static co efficient of friction μs = 0.3. (Image is attached below)...

Unless he meant the magnitude of the tangential acceleration? Which would be zero each time? But he doesn't say that

Written by a mechanics lecturer in my college but unfortunately I haven't had a reply to any email I've sent him. The questions the other two years were: 1. A particle travels around an elliptical path with a constant speed of 1 m/s. If the equation of the ellipse is 3x2 + 2y2 = 2 Determine...

Dang just when I thought I had it. Well I'm guessing the equation will change to b2/a? Although that gives me 1/√3 which when subbed into a doesn't result in an answer? Edit: I was going under the assumption that a and b are the two radii? So whichever is smaller I just sub...

Had an entire post written and then realized that it's the smaller radius but furthest from centre of the ellipse. Ok so taking that into account would the answer be 1? Minimum radius = 1 a = (v^2)/r = 1/1 = 1?Edit Thank you, can't believe I didn't get that >.< That's a great help.

Yes but isn't the maximum centripetal acceleration when the particle is traveling at the point of largest radius?

This is the maximum radius of curvature.

This is a mechanics question which has come up a number of times in end of year exams in my college, I hope this is the right forum to post it in. Homework Statement A particle travels around an elliptical path with a constant speed of 1 m/s. If the equation of the ellipse is (x^2)/3 + y^2...