Recent content by Kalkunipraed

I plotted it in Matlab before I wrote my previous post. And yes, It was basically straight. The 5C/1hour was an excerpt from the whole dataset (plotted in the first post). You gave me much to work with. Thank you, I will try to crack it tomorrow.

If I understood your initial equation correctly, it means to core of the calculation is: WC_p\frac{dT}{dt} For example to raise 5C in 1hour: 0.14 * 1005\frac{5}{3600}=0.195...W/h And Joules needed to heat that amount of air by 5C 0.14*1005*5=702Joules All this seems to be the second equation...

For example, I found a calculation showing how much energy is needed to heat a cubic meter of air by 1C. The weight of air is 1.205 kg/m3 @ 20C The specific heat capacity of air is 1.005 kj/kg @ 20C So If my inner area is 0.1134 m^3, then to raise the temperature of it by 5C i would require...

Short version: If I have an insulated container(box) of some specific size. The inside temperature is temperature X. Ambient temperature is Y. Also X < Y. The box starts warming up. I log the inside temperature over time with data points. How can I determine one or more of the following based...