Recent content by Kanesan

  1. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    I am thinking that all co-movers are in same frame! Not to confuse with too many frames if they are co-moving. Is it wrong? I have difficulty grasping this. If we assume rest (temporarily or permanently), doesn't that mean velocity is zero? We have calculated only once. Just one experiment...
  2. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    Hi Harold, I understand that we can change frames and whatever frame we are in is the rest frame meaning that all the observations we make within our frame will follow same physics laws. I feel that the use of the word "rest" frame unnecessarily complicates things because everyone/everything is...
  3. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    We have extensively analyzed the experiment from the view of observer in the aether frame. I am able to completely understand it. So, we know what result an observer staying with aether should get. But, all MMX data are taken from the experiment frame which is not in the aether frame (unless...
  4. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    Thanks Harold. I got it all finally. Thanks again for all your patience and staying with me until the last point. I greatly appreciate it.
  5. K

    Testing Liquidified HCl: Corrosive Effects & Litmus Paper Results

    I understand Borek's caution. But pH is only a -ve log of "proton" concentration and can be used for all systems. Just we cannot assume 7 is neutral, that is specifically for water; generally acids and bases are defined with that 7 in mind. I take TeethWhitener's "more basic" as just relative...
  6. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    Hi Harold, I am using only Huygens construct and from what I can easily understand (still no paper and pencil, only mental picture!), there will be no angle change if the beam hits the mirror at 90 degrees. That will not be the case here because of the changes at the inclined mirror. I have...
  7. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    Hi Harold, Thank you very much for that reference. It was great help. I really appreciate it. It is interesting to note that it took more than a year to get accepted and 1.5 years to be published, in 2004. It also mentions an earlier paper (R. A. Schumacher, ‘‘Special relativity and the...
  8. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    Hi Harold, Thanks a lot for expanding my knowledge in this area! I will send a PM to get even more!
  9. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    Mere mention of shrinking Microsoft Paint made it easy to visualize the angle changes on length contraction (even without drawing!). It looks to me that on extreme contraction all angles will reach 90 (and on extreme stretching all angles will reach zero) degrees. So, to the observer in the same...
  10. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    Hi Harold, I came across that Wikipedia article earlier but since I was focused on moving mirror and I could not find one there, I missed the correlation. That first picture shows about normal refraction, and no reflection considerations. I don't know much difference between the two except that...
  11. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    Thanks Harold, I have not read about Huygens construction. I have to read about it (the link to the paper in that post no longer works). May be that will help. But length contraction and changing angle are a bit confusing. Won't the length contraction be zero and the angle be same as claimed (45...
  12. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    Hi Peter, I am also not able to see the beam width info. I understand that this was to "test" the old theory. But I just wanted to see if I can derive and see how their explanation was working even with the "ad hoc" length contraction which is not "classical". I thought the setup and math was...
  13. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    The two beams have to overlap back to create Fringe effect I am assuming. So, that's why taking this difference seriously. If it was 1 inch beam, 2mm will not make any difference! But if it is 1 mm beam, they can stay separately without any Fringe effect. But if this was true, we will see...
  14. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    The shift of 2*v*t I am calculating in my path position calculation comes to about 2 mm (for 10 m arm length). Still I am not understanding why I am getting the path differently but just for the fun of it calculated how much it will be! C = 300,000 km/s; v = 30 km/s; L = 10 m 2*v*t = 2*v*L/C =...
  15. K

    Understanding the MMX Calculation Problem: Vertical vs. Horizontal Analysis"

    Hi Peter, I am getting the horizontal calculations correctly. That's why not focusing on that part. It goes along the same line all the time and the path length are easy to calculate. Also where it will hit the inclined mirror will never change. As others have mentioned, I used the...
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