Recent content by Kc emefo

  1. K

    Thermodynamics -- Internal Energy

    Oh thank you very much sir,I just figured out my mistake and corrected it Am grateful for that correction
  2. K

    Thermodynamics -- Internal Energy

    Oh I got that,jus substituted 2.8×10^3 instead of 2.8×10^6 and my V2=1.5792 which is wrong,am still not getting the suppose as V2=0.148
  3. K

    Thermodynamics -- Internal Energy

    Substituting with the value of P1=28bar V1=0.06 and n=2 into the given equation: 2.8× 10^6×0.06^2(1/V2-1/0.06)=-100 Opening bracket: 10080(1/V2-1/0.06)=-100 10080/V2-1/0.06=-100 10080/V2-16.66=-100 Cross multiple and make V2 subject of formula: 10080-16.66=-100V2 10063.34/-100=-100V2/-100...
  4. K

    Thermodynamics -- Internal Energy

    Thank you,can you help me out with the appropriate substitution to arrive at the given answer V2=0.148m @berkeman
  5. K

    Thermodynamics -- Internal Energy

    I tried substituting into this formula you used but am not getting V2=0.148,am getting different answer.can you show your working here on how you got V2= 0.148 given the intial pressure and volume
Back
Top