Recent content by keropi080

That was a pretty nice simulation. :D

The straws are around 10 inches, and flimsy. They're not the bendy kind, though. That's what I was thinking from the start. Though I need another plan in case the tower thing doesn't work.

I'm working on a little project here. I'm supposed to build a bookstand made out of around 50 straws and tape. They're the only materials I'm allowed to use.It's supposed to be able to hold my hardbound physics book, which is 2.5kg, for more than a minute. The higher the book is from the...

I get it now! Thank you so much! I didn't what that first sentence meant. I overlooked it. Thanks again!

1.) Along the x-axis, on the walls. 2.) The friction forces are at their maximum, which means that whichever direction he's going, up or down, he's being supported by his feet and back! Even if he let's go of the rope, he's still in equilibrium! Wow, big realization. :O

Reading your reply made me think. Maybe I misunderstood the question... He doesn't necessarily have to move up? So that means, the normal force being asked on the question are the forces he exerts on his feet and back? Is that right?

Let's see. Since both normal forces are equal... Fn = Fnx(0.80+0.60) + 686N - Ft Fn = Fnx(1.40) + 686N - Ft I can't cancel out Fn because, as you said, they're not the same. How do I get the values of the remaining variables?

On the opposite walls? But then, the normal force on opposite sides would have to be equal, since he's not moving in the x-direction?

Homework Statement The 70-kg climber is supported in the "chimney" by the friction forces exerted on his shoes and back. The static coefficients of friction between his shoes and the wall, and between his back and the wall, are 0.80 and 0.60, respectively. What is the minimum normal force he...