Recent content by kevi555

Hi, I'm looking at question #33 of the linked book on page 391. http://books.google.ca/books?id=4fXFO-0B6f4C&pg=PA391&lpg=PA391&dq=zero+magnetic+fields+proof&source=bl&ots=ZmVev2Wdpb&sig=_P2-p3xN29sgIKC3aNsp8N15xCo&hl=en&ei=ExrUSaukIIWsnAfRteDzDg&sa=X&oi=book_result&ct=result&resnum=1 I...

Hi there, I'm looking for a series that expands to look like : (pi^2)/3! - (pi^4)/5! + (pi^6)/7! - ... =1 Any ideas would be greatly appreciated as I can't seem to get anywhere with it! Thanks, K

Hi, I was wondering what the physics are behind why a turkey wishbone breaks in just one spot of the bone when one person is pulling from either side of the wishbone trying to break it? Thanks!

Alright, I can picture the Acos\theta and Asin\theta on the horizontal and vertical axes, respectively. I don't understand how the z is still in the derivative equation?

Please note, I made an error in my first post...it is now correct.

Hi, If z=Ae^{i\theta}, deduce that dz = iz d\theta , and explain the relation in a vector diagram. I know that z = x + iy but I don't know if that's going to help. Any hints or tips would be appreciated! Thanks!

Okay, so I've found that the velocity at that time (0.05291) is -0.8715. I know that the displacement in y is 2.5 cm. I'm not quite sure how'd it proceed from here though.

Hey all, I trying to get somewhere with the following problem and am not having much luck. Any tips or suggestions would be appreciated! I found that the block leaves the platform at y=2.5 cm though. A platform is in SHM in the vertical direction with an amplitude of 5cm and freq. of 10/pi...

Hey all, I trying to get somewhere with the following problem and am not having much luck. Any tips or suggestions would be appreciated! I found that the block leaves the platform at y=2.5 cm though. A platform is in SHM in the vertical direction with an amplitude of 5cm and freq. of...

"W" as in work? or what variable?

Just a question about gravitation equations: Neglecting Earth's rotation, show that the energy needed to launch a satellite of mass m into circular orbit at altitude h is equal to: (\frac {GMm}{R})(\frac{R+2h}{2(R+h)}) Where R = the radius of the Earth and M = the mass of the Earth...

Just a question about gravitation equations: Neglecting Earth's rotation, show that the energy needed to launch a satellite of mass m into circular orbit at altitude h is equal to: (\frac {GMm}{R})(\frac{R+2h}{2(R+h)}) Where R = the radius of the Earth and M = the mass of the Earth...

A chair is attached by a 9.0m long chain to the top of a tall rotating tower. The tower spins the chair and rider around at a rate of 1 Rev. every 4.0s. Max weight of the chair & rider is 150kg. You buy chain rated@3000N of tension. Will that chain be strong enough?