SHM Platform Block Displacement

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The discussion focuses on a problem involving a block on a vertically oscillating platform undergoing simple harmonic motion (SHM). The platform has an amplitude of 5 cm and a frequency of 10/pi vibrations per second. The block is placed at the lowest point of the platform's path and is observed to leave the platform at a height of 2.5 cm. Participants discuss the block's velocity at separation, which is calculated to be -0.8715 m/s, and express uncertainty about the next steps in solving the problem. The conversation emphasizes the transition from SHM to trajectory analysis after the block separates from the platform.
kevi555
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Hey all,

I trying to get somewhere with the following problem and am not having much luck. Any tips or suggestions would be appreciated! I found that the block leaves the platform at y=2.5 cm though.

A platform is in SHM in the vertical direction with an amplitude of 5cm and freq. of 10/pi vibrations/sec. A block is put on the platform at the lowest point of its path. How far will the block rise above the highest point reached by the platform?

Thanks!

K
 
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kevi555 said:
Hey all,

I trying to get somewhere with the following problem and am not having much luck. Any tips or suggestions would be appreciated! I found that the block leaves the platform at y=2.5 cm though.

A platform is in SHM in the vertical direction with an amplitude of 5cm and freq. of 10/pi vibrations/sec. A block is put on the platform at the lowest point of its path. How far will the block rise above the highest point reached by the platform?

Thanks!

K

How fast is the block going when it separates from the platform? Where will it separate from the platform? Then it's a trajectory problem.
 
Okay, so I've found that the velocity at that time (0.05291) is -0.8715. I know that the displacement in y is 2.5 cm. I'm not quite sure how'd it proceed from here though.
 
kevi555 said:
Okay, so I've found that the velocity at that time (0.05291) is -0.8715. I know that the displacement in y is 2.5 cm. I'm not quite sure how'd it proceed from here though.

What is that calculation that gave you the numbers?
 

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