Recent content by khannon5

No but in the beginning it has no pe

But why does it have pe if it's on the ground

Would the pe just be the mgh of the weight above the ground?

Ke=.5mv^2 of mass 1 + .5mv^2 of mass 2 + .5Iw^2 of pulley

Kinetic energy of each mass and the rotation of the pulley

Homework Statement Two masses are connected by a string that hangs over a frictionless pulley with mass 8kg, radius .25m, and moment of inertia .5mr^2. One mass lays on the ground and has mass 15kg. The other mass is 22.5 kg and is 2.75 m above the ground. Use conservation of energy to...

Ok thank you so much. I really appreciate your time

.085 kg but this can't be right what am I doing wrong?

Torque = rfsintheta but in this problem sintheta=1. I found the torque of gravity to be .0833 from that equation if that's cprrect? So I have .0833 = .1 X f. Solve for f and get f = .833 N. I divide this number by 9.8 to get

The force of gravity acts on the whole thing but the center of gravity is in the center Torque is a force that causes a rotational change to something

I don't know where the fact that the fulcrum is .1m away from the center of gravity comes in and how to find the mass of the stick after finding the torque of gravity

9.8 X mass My teacher isn't very good so I'm usually left to try and figure everything out on my own

I'm not sure how to put it in the equation..would it be torque of gravity / .1m?

Torque 1 = .294Nm Torque 2 = .2107Nm -.294 + .2107 + torque of gravity = 0 The force of gravity acts .1m away from the fulcrum

Would it be torque of mass 1 + torque of mass 2 + torque of gravity = 0