Two masses hanging from a pulley (conservation of energy)

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Homework Help Overview

The problem involves two masses connected by a string over a frictionless pulley, with specific details about the masses, pulley characteristics, and the application of conservation of energy to determine the speed of one mass when it reaches the ground.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the conservation of energy principles, questioning how gravitational potential energy is converted and where it goes in the system. There are considerations of the kinetic energy of both masses and the rotational energy of the pulley.

Discussion Status

Participants are actively exploring the relationships between potential and kinetic energies, with some guidance offered on formulating an energy equation that includes all relevant energies. There is a recognition of the need to clarify the role of potential energy for the mass on the ground.

Contextual Notes

There is a discussion about the reference point for potential energy and the implications of one mass being on the ground, which raises questions about its potential energy status at different points in the system's motion.

khannon5
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Homework Statement


Two masses are connected by a string that hangs over a frictionless pulley with mass 8kg, radius .25m, and moment of inertia .5mr^2. One mass lays on the ground and has mass 15kg. The other mass is 22.5 kg and is 2.75 m above the ground. Use conservation of energy to determine the speed of the 22.5 kg mass when it hits the ground

Homework Equations


Ke final = pe initial
Ke=.5mv^2 + .5Iw^2

The Attempt at a Solution


I found the pe of the 22.5 mass using pe=mgh. I made that equal the ke equation but I'm not sure whether to combine masses or what to use
 
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The system loses gravitational PE. The first question is to ask where does this energy go?
 
There are three elements to the system, the two masses and the pulley. Consider the total energy (KE and PE) of each at start and again at the moment of impact.
 
PeroK said:
The system loses gravitational PE. The first question is to ask where does this energy go?
Kinetic energy of each mass and the rotation of the pulley
 
khannon5 said:
Kinetic energy of each mass and the rotation of the pulley

Can you write down an energy equation involving all the energies gained and lost?
 
PeroK said:
Can you write down an energy equation involving all the energies gained and lost?
Ke=.5mv^2 of mass 1 + .5mv^2 of mass 2 + .5Iw^2 of pulley
 
khannon5 said:
Ke=.5mv^2 of mass 1 + .5mv^2 of mass 2 + .5Iw^2 of pulley

OKay, but there's no PE there.

You're also going to have to find a relationship between the various KE's. So, you need to think about that as well.
 
PeroK said:
OKay, but there's no PE there.

You're also going to have to find a relationship between the various KE's. So, you need to think about that as well.
Would the pe just be the mgh of the weight above the ground?
 
khannon5 said:
Would the pe just be the mgh of the weight above the ground?

There are two masses involved.
 
  • #10
PeroK said:
There are two masses involved.
But why does it have pe if it's on the ground
 
  • #11
khannon5 said:
But why does it have pe if it's on the ground

Does it stay on the ground?
 
  • #12
PeroK said:
Does it stay on the ground?
No but in the beginning it has no pe
 
  • #13
khannon5 said:
No but in the beginning it has no pe
Right (assuming ground is taken as the reference point for PE). So post the initial energy = final energy equation.
 

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