Recent content by kheila

Agh! Thanks for helping me through this :)

Ok. So, solving that equation for B: B = mg/(I*L) = (1.6 kg)*(9.8 m/s^2) / (I*.63 m) I = R/V = 11 ohms/20V = .55 A Plug this in: B = (1.6 kg)*(9.8 m/s^2)/(.55A*.63m) = 45.25252525... T But this is not the right answer. And that's almost exactly what I did the first time.

Doesn't theta = 90 degrees, so the sin(theta) term can be dropped? Also, this is the second part of a two-part problem. In the first part, it was established that the magnetic field is perpendicular to the "paper." I see how the equation can be simplified, as you showed. However, I don't...

Homework Statement A heavy conductor (mass m, length [FONT="Courier New"]l, resistance R) is suspended by two springs each with spring constant k, and connected to a battery with electric potential V as shown in the figure. A magnetic field B is now imposed. The acceleration of gravity is 9.8...

Nope, still working on it...

[SOLVED] Coulomb's Law question - find initial charge Homework Statement Two identical small metal spheres with q1>0 and |q1| > |q2| attract each other with a force of magnitude 55.4 mN. They are separated by a distance of 3.94 m. The radius of each sphere is 40 micro-Newtons. The...