Coulomb's Law question - find initial charge

AI Thread Summary
The discussion revolves around solving a Coulomb's Law problem involving two metal spheres with unequal charges that initially attract and later repel after coming into contact. The user successfully calculates the total initial charge using the force and distance but struggles to isolate the individual charges, q1 and q2. They derive equations relating the charges before and after contact, ultimately determining the change in charge (Δq) and attempting to find q1. After multiple edits and calculations, they arrive at a value for Δq but still seek confirmation of the final answer for q1.
kheila
Messages
6
Reaction score
0
[SOLVED] Coulomb's Law question - find initial charge

Homework Statement



Two identical small metal spheres with q1>0 and |q1| > |q2| attract each other with a force of magnitude 55.4 mN. They are separated by a distance of 3.94 m. The radius of each sphere is 40 micro-Newtons.

The spheres are then brought together until they are touching. At this point, the spheres are in electrical contact so that the charges can move from one sphere to the other until both spheres have the same final charge, q.

After the charges on the spheres have come to equilibrium, the spheres are moved so that they are 3.94 m apart again. Now the spheres repel each other with a force of magnitude 6.648 mN.

The Coulomb constant k is 8.98755x10^9 N*m^2/C^2.

What is the initial charge q1 on the first sphere?

Homework Equations


F = k*|q1*q2|/r^2


The Attempt at a Solution


I can get as far as figuring out the TOTAL initial charge of q1*q2. That's easy: |q1*q2| = F*r^2/k. What stumps me is how I can figure out what only ONE of them is -- the problem states that they're not equal, but I can't for the life of me figure out how to get an exact number. I'm guessing it has something to do with the fact that first, they are attracted to one another and then they repel after reaching equilibrium.

----EDIT 2/10-----
OK, here's what I've done since I posted, it's still not giving me the right answer, though.

Before touching:
F1 = k * |q1*q2| / r^2

After touching:
F2 = k * q^2 / r^2 (where q is the charge on each of the spheres, since they both have the same charge)

The initial charge on q1 is equal to the final charge on q plus the change in charge; that is,
q1 = q + Δq
Similarly, q2 = q - Δq

Now solve for Δq:
F1 = k * |q1*q2|/r^2
Rearranging and replacing q1 and q2,
F1 * r^2 / k = | (q/2 + Δq)*(q/2 - Δq) |
= | (q/2)^2 - (Δq)^2 |

This means that F1*r^2/k is equal to either (q/2)^2 - (Δq)^2 or (Δq)^2 - (q/2)^2, due to the absolute value signs.

This yields two possible values for Δq. The second one I get is greater than the value for q, so I assume this is a 'garbage' value (because this would mean that q2 = q - Δq would yield a negative value, which makes no sense in this situation) so I use the first value I get for Δq.

Then, I solve for q1: q1 = q + Δq. However, this answer is wrong.

-----EDIT again, 2/10-----

OK, got it. Here's what I did:

EQUATION 1: F1 = k * |q1*q2| / r^2
EQUATION 2: F2 = k * q^2 / r^2 (where q is the charge in one of the spheres -- they are equal. Absolute value signs are left out since they are redundant, as q is squared)

EQUATION 3: q1 = q/2 + Δq
(In words, the initial charge for q1 is equal to the final charge of q1 plus however much charge left q1 when the spheres touched).

EQUATION 4: q2 = q/2 - Δq
(In words, the initial charge for q2 is equal to the final charge of q2 minus however much charge it gained when the spheres touched).

Replace q1 and q2 in equation 1 with their values from equations 3 and 4:

F1 = k * | (q/2 + Δq)*(q/2 + Δq) | /r^2

Rearrange this equation to bring k and r to the other side, and expand what's inside the abs. value signs:

F1 * r^2 / k = | (q/2)^2 - (Δq)^2 |

Now, the left side of the equation can be equal to two possible things (because of the abs. value signs):

-[(q/2)^2 - (Δq)^2] or +[(q/2)^2 - (Δq)^2]

Expanding: (Δq)^2 - (q/2)^2 or (q/2)^2 - (Δq)^2

Set each of these equal to F1 * r^2 /k and solve for Δq. The first one yields a non-real result (Δq^2 = -8.40899528017e-11...you can't take the square root of a negative number) so the correct one to use is the second:

F1 * r^2 /k = (q/2)^2 - (Δq)^2

Plugging in the values for F1, r^2, k, and q, and solving for Δq, I get Δq=1.0357970386e-5.

Now plug this value into equation 3 to get the value for q1.

Hope this solution helps anyone else who's stuck on a problem like this!
 
Last edited:
Physics news on Phys.org
Do you have the final answer this by any chance?
 
Nope, still working on it...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top