Recent content by kidkook

Excellent. This is exactly what i was looking for. A very well documented explanation. Many thanks.

Sorry for the confusion. What i have is a dataset with 16 different values. What I'm trying to achieve is to determine how many combination are available without repetition/duplication of a value. So i know the answer is 65536. I achieved this by using the above formula 16 times and...

I have 16 items and i need to know the number of possible combination for all 16 items. I know the possible number of combination for all 16 items is 1 and the possible number of combinations for 15 of the 16 items is 16 using the formula below: \frac{n!}{r!(n-r)!}. How can i adaprt this...