ok, ok. so I didn't need to do two magnetic field strength equations? If I let I=6, I get B=1.131. The flux inside the conducting loop then is 0.00142, and Es would be -.00142 for one second. Then I can finally solve for M to get 2.369*10-4. I hope I've done it right this time. It makes a...
Ok, I see that I need the change in magnetic flux to calculate the Emf of the inner conducting loop, but I still can't calculate that without a single hint about magnetic field strength. I thought I could figure out the change in field strength by doing two calculations of
B=uo(N/L)I.
I made...
Apparently he insists that the answer is 2.21 x 10-3 T. I don't think that's what you would get calculating for the magnetic flux density, but if it is, how can you tell he's asking for that is the problem? I gave you the exact words he asked.
Homework Statement
A 0.100m long solenoid has a radius of 0.05m and 15000 turns. The current in the solenoid changes at a rate of 6.0 A/s. A conducting loop of radius 0.0200m is placed at the center of the solenoid with its axis the same as that of the solenoid. Determine the mutual...
Homework Statement
A 1.2 kg rod that has a length of 1m and a resistance of 5 ohms slides with constant speed down a pair of frictionless vertical conducting rails that are joined at the bottom. Other than the rod, the rest of the circuit is resistance-less. A uniform magnetic field of...
This is driving me insane. This is all I can think of to do, and my teacher said it was wrong.
A solenoid of length 0.25m and radius 0.025m is comprised of 440 turns of wire. Determine the magnitude of the magnetic field at the center of the solenoid when it carries a current of 12 A...