Recent content by kitkat2950

  1. K

    Work Done on Proton by +3microC Charge: Find V at 50cm & 35cm

    A proton is moved at a constant velocity towards a stationary +3micro coloumb point charge that cannot move. The proton is initially 50 cm away from the point charge and the proton is moved until it is 35 cm away from the point charge. A) How much work was done on the proton? B) If released...
  2. K

    What is the entropy change of the meteor

    A 3400kg meteor (c=450 J/KgC) at 1250 degrees C falls into lake michigan, which is at a temperature of 12 degrees C. Assuming the temperature of the lake remains constant, A) What is the entropy change of the meteor as it reaches thermal equilibrium with Lake Michigan? B) What is the total...
  3. K

    Induced voltages and step-up transformers

    I have been trying, but I still have 3 problems I can't get. 1)A simple generator has a 600 loop square coil 18.0 cm. on a side. How fast (in rev/s.) must it turn in a 0.730 T. field to produce a 120-V. peak output? I think I need to use the equation Emax=NBAw. N=600 B=.730 A=.0324...
  4. K

    Energy of a proton around a magnetic field

    Oh thank you. I knew it had to be something stupid. It was right!
  5. K

    Energy of a proton around a magnetic field

    So velocity is v=.075m X 1.6X10^-19C X 4.30T / 1.67X10^-27. Which equals 3.09X10^7. I then used KE=.5 X 1.6X10^-19 X (3.09X10^7)^2 and came up with 7.637X10^-5J. I multiplied that by 1eV/1.6X10^-19J and got 4.77X10^14. But it was still wrong. Any other suggestions?
  6. K

    Energy of a proton around a magnetic field

    Thank you, I love House by the way. I would say it has kinetic energy. SO would I use KE=1/2mv^2? But then I always get confused on what work equals, because I think I need to find work to solve the equation. I think W=KE+PE, and I don't think there is any Pe. Would the work just equal the...
  7. K

    Energy of a proton around a magnetic field

    A proton moves in a circular path perpendicular to a 4.30 T. magnetic field. The radius of its path is 7.5 cm. Calculate the energy of the proton in electron-volts. I'm not sure which equation to use. I tried using m=rqB/v and found the velocity. However, I'm not sure how to relate that...
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