Recent content by KOKA

Okay, I think I got it. In part c, because the car does not move up or down the bank, the magnitude of the centripetal force is equal to the magnitude of the force of static friction. I think I got the answer to that the first time I attempted it. Then, in part d, I accidentally used normal...

I checked, there's nothing. The booklet was just recently photocopied, so I don't think they'll have any listed for a while. I'll try looking into it a bit more, and then post the closest answer I can get in here so maybe other people who need it can look it up. Thanks anyway Doc Al.

I'm learning independently right now so all I've got is a booklet, and it's made a few mistakes so far. This is one of the questions in there. I'm guessing I have to assume that it's banked for that particular speed or I wouldn't be able to solve it, or maybe I'm just going about it the wrong...

I've attempted to solve this problem but I'm not really sure if I'm doing it right. I've looked up other threads containing the same question, but they just don't have the answers I'm looking for. Thank you in advance to anyone who helps. Homework Statement A race-car driver is driving her...

Yeah! I see now! I kept looking at the question as if the box was in motion already, and we needed to apply a force for it to stay at rest. Instead, the box is already at rest and we just need to know the amount of force that can be applied to challenge the maximum static friction and force of...

I'm just a senior at high school so I'm no pro at this, but doesn't friction act in the opposite direction of motion? The box is moving down the ramp, so friction has got to be in the opposite direction. If you look at it, 270N is a lot of force to be applying to a box. Edit: Looking back...

Without any added parallel or perpendicular forces, the force of gravity acting parallel to the ramp will move the box downwards. In this case, you're looking for a larger normal force to keep the box in place (think about adding pressure from a hand to prevent the box from slipping). Remember...

The force of gravity parallel to the ramp is pushing the box down, and the force of friction is acting up the ramp in order to prevent its motion. In this state, Fnet is not equal to 0, and the box is being pulled downwards by gravity. The equation in this situation is: Fnet = FgR - Ff You've...