Recent content by kpizzano
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K
Laurent Series Expansion coefficient for f(z) = 1/(z-1)^2
Ok, thanks so much for commenting!- kpizzano
- Post #5
- Forum: Calculus and Beyond Homework Help
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K
Laurent Series Expansion coefficient for f(z) = 1/(z-1)^2
I just noticed that I missed the part in the problem statement that says valid for |z|>1 , so I only need \sum_{n=0}^{\infty}\left(n+1\right)z^{-\left(n+2\right)}. I got that by noticing that \frac{1}{\left(z-1\right)^2} = \frac{1}{z^2\left(1-\frac{1}{z}\right)^2} Using the...- kpizzano
- Post #3
- Forum: Calculus and Beyond Homework Help
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K
Laurent Series Expansion coefficient for f(z) = 1/(z-1)^2
Homework Statement Determine the coefficients c_n of the Laurent series expansion \frac{1}{(z-1)^2} = \sum_{n = -\infty}^{\infty} c_n z^n that is valid for |z| > 1. Homework Equations none The Attempt at a Solution I found expansions valid for |z|>1 and |z|<1: \sum_{n =...- kpizzano
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- Coefficient Expansion Laurent series Series Series expansion
- Replies: 4
- Forum: Calculus and Beyond Homework Help