Recent content by krackedude

So, normally for a cone would have a θ from 0 <= θ <= 2∏, but the question says first octant, so would that mean 0 <= θ <= ∏/4? And ∅ would be: 0 <= ∅ <= ∏/4? EDIT: wait, wouldn't θ be limited by 3x <= y <= 4x? So, then how could i find those limits?

Well, it's a cone. Here's a picture: http://img829.imageshack.us/img829/7083/graphi.png

Homework Statement http://img28.imageshack.us/img28/7118/capturenbc.jpg Homework Equations x2 + y2 + z2 = p2 http://img684.imageshack.us/img684/3370/eq0006m.gif The Attempt at a Solution Using the relevant equations I converted the given equation to: ∫∫∫e(p3/2) * p2 *...

Wow...I can't believe I missed that one. x = 3 and y = 5, so the given values can be used to calculate it. Thanks a lot! Edit: yeah, i definitely screwed up ∂x/∂s, and ∂x/∂t...Thanks!

Homework Statement Calculate ∂f/∂s + ∂f/∂t at s = 2, t = -1. Given: f = f(x,y) x = s - t y = s2 + t2 ∂f/∂x (3,5) = 0.06170 ∂f/∂y (3,5) = 0.06170 Homework Equations ∂f/∂s = ∂f/∂x * ∂x/∂s + ∂f/∂y * ∂y/∂s ∂f/∂t = ∂f/∂x * ∂x/∂t + ∂f/∂y * ∂y/∂t The Attempt at a Solution...