Recent content by kripenwah

Numerator will be -1 or 1. Divided by infinity it evaluates to 0. But I am not sure if that is a valid way to show that it evaluates to 0. In the book I am using (Stewart) it gives a therom if Lim n-> infinity |an = o than Lim n-> infinity |an = 0.

I don't see how it helps unless you take the absolute value of it.

Not sure if I wrote the problem bad. Here is what the problem looks like the text. an=

Well the problem text says Determine whether the sequences converges or diverges. If it converges find the limit.

The limit is to infinity. http://www4d.wolframalpha.com/Calculate/MSP/MSP44701a03g21d31b6h65500003b8813i95da1dcbe?MSPStoreType=image/gif&s=25&w=119&h=40

lin n -> oo abs (((n(-1)^(n-1))/(n + 1/n)) * (1/n)) So it ends up being (infinity/infinity) * 0 = 0. Is that really a valid way to evaluate it?

Homework Statement An = (((-1)^(n-1))n)/(n^2 + 1) I need to know if it converges or diverges and if it converges the limit. Homework Equations The Attempt at a Solution I know it converges to 0. But I don't know how to show it when evaluating. I tried evaluation An| in the...