Summary:: Calculate the deformation on a rod/axle/pipe due to a distributed load.
I’m manually trying to calculate the deformation on a rod/axle/pipe due to a distributed load. The rod has an outer diameter of 62mm and an inner diameter of 50, is 170mm long, made from a material with an...
https://repository.am.szczecin.pl/bitstream/handle/123456789/1186/30-zn-am-45-117-walus-p.pdf?sequence=1
^ paper regarding the operation.
The picture shows the heeling i mentioned. If you look at the cable on the left fairlead, it is no longer positioned in the groove.
Quoting from the...
Please do tell me how it works.
My view is that the cable will stay in the groove and rotate around the fixed axis with the fairlead, as long as the static friction between the cable and groove surface is equal to the applied force. When the cable slips and travels up the grooved walls, the...
The question is based of a real problem that ocured during a marine Seismic survey. The convetional fairlead design is the right sketch. When the vessel is turning the widest fairleads will experience heeling, and it has occurred that the cable manages to “climb” the inside walls of the groove...
The torque is occurring due to the vertical force acting on the cable. The momentum will be greater on the right fairlead, as well as the moment of inertia (simplification where only the cable and block has mass). The right fairlead will with the same acting force experience less torque, but...
Thanks for your reply! The inertia gets greater the longer the mass is from the rotating axis. Does this not mean that if the two fairleads have the same mass, it will be “easier“ to rotate the left fairlead? I am trying to figure out pros and cons with both sulutions, so any further views is...
This is a theoretical question where we should explain and show with formulas which option is the best solution for avoiding cable to slip from groove. I believe that since the cable center is closer to the rotation axis (left fairlead), the force on the cable will move the fairlead as well (as...