Recent content by ksinclair13

Write v (an arbitrary vector in V) as a linear combination of v1, v2, and v3 and then see if you can write v as a linear combination of just v1 and v2. Hint: v3 = v1-v2.

It's acceleration is constant. The answer is A. I made a foolish assumption. Thank you for the help! Edit: If I knew the question meant that, I would have said A without a doubt (re-read my first post).

Here is a question on a quiz I took the other day: An object is in free fall in a vacuum. Which of the following is true? A. Velocity is increasing B. Acceleration is increasing C. A and B D. None are correct I might be thinking about this wrong, but I assumed it was a vacuum in...

It's interesting that you say that because with my school's math program, you do not learn certain important things like this before taking calculus. It's because we have a ridiculously bad integrated program (Math I, Math II, Math III, and Math IV) where all areas of math are covered lightly...

The only way you could "beat the system" is if it wasn't random.

I don't have a chart with me, but I think the answer for the first one would be the one with the lowest standard reduction potential. The answer to the second one would be the one that has a lower reduction potential than Fe3+.

What is SO4++? I think you meant SO42-, which is a conjugate base and not an acid. SO42- will NOT react with OH- because both want to accept a hydrogen ion. It WILL react with H2O, however. First, I'd start out by writing out the ions dissociated. KNO3 is soluble, NaOH is a strong base so it...

Try multiplying the entire thing by \frac{\sqrt{18}}{\sqrt{18}} and see where you can go from there.

I thought that every positive real number has two square roots and that the square root sign indicates the positive square root.

You did the problem correctly. You end up having to solve the quadratic equation 30.x2 - 31x + 7.5 = 0. You get the answers of x = .39 and x = .65. Now, think about the problem. You are starting with 1.0 M NO2, correct? You should notice that the equilibrium concentration of NO2 will be 1.0...

That is great so far and is farther than many people would've gone to explain this. If you remove red meat, it is the same as removing NaC5H3N4O3, which will cause the system to shift to the left to undo that change.

Okay, thank you. :wink: I always use the quick reply, but now I know how to do it with that as well :smile:

Looks good, but your second answer should have one more significant figure. Try looking for a table or appendix somewhere in your book to find the standard enthalpies of certain substances. Or you could check out this link: http://www.psigate.ac.uk/newsite/reference/chemdata/3.html

Thank you Doodle Bob for clearing that up for me.

Well 0! = 1, so I don't think that would be a problem ;)