I get what you mean. I agree.
I probably didn't phrase it that well. I meant I don't want to lose control and end up in unfavourable circumstances career-wise, considering the small percentage of people who get assimilated into the academia. I'm okay with academic challenges.
Bleh. I regret...
What courses can I pursue after my undergrad education that will enable me to work on next gen nuclear technologies?
What kinds of people work in these areas and what career paths do they choose?
I've read a lot about the different kinds of people working on Gen 4 reactors(LFTRs, TWRs) and...
In case of the Delta baryon, it exists in four resonance states: two are excited analogues of the neutron and the proton and the other two are totally different. All four have different quark content. What I'm asking is in case of K1(1270) : is it an excited version of a certain kaon(and if so...
Hi. I'm trying to study QM from Shankar on my own. Asking this here because I don't really have a teacher to help me with this:
Homework Statement
I'm trying to solve problem 1.8.9 -part 3 of "The Principles of Quantum Mechanics" by R Shankar. Here's the problem:
Given the values of Mij (see...
What about K1 (1270) though? It's straightforward if you are dealing with a direct analogue like K0 and K*0.
What if it's K2 K2*, with completely different masses(1420 vs 1770)? Or K1 (1270) K1(1400)? Is their quark content identical despite the mass difference? If so why?
Maybe I'm having...
I thought since there are neutral and charged varieties of K*892, K1(1270) must have something similar going on... And as soon as their charges differ, their quark content would vary according to what's given in that box right at the top of the first page.
What is it's quark content then? There...
Hi. I was reading an introductory book about particle physics and I visited the PDG for an exercise.
I found this...
http://pdg.lbl.gov/2014/tables/rpp2014-tab-mesons-strange.pdf
On page 9, the data of K1(1270) is given. How do I figure out it's quark content? If I look at the data for K*(892)...