Unfortunately, I used my approach on an exam, that's why I'm so keen on knowing if it's correct. Would have used the comparison, but alas, I didn't occur to me at the time.
Oh, mine wasn't complete, p needs to be different from 1.
The better question;
if n < n * sqrt(n^2-1) < n^2, does that mean there exists p such that n * sqrt (n^2 -1) = n^p ?
Ok, let me restate. Can all positive real numbers x be written as n^p, where n and p are real numbers?
Or
if n < n * sqrt(n^2-1) < n^2, does that mean there exists p such that n * sqrt (n^2 -1) = n^p ?