Recent content by Kung-Fu

Alright, I got it down now. Thank you very much for your help!

E(int)=9.11e-31*9e16=8.199e-14 J and deltaKE=(1.667-1)9.11e-31*9e16=5.46627e-14 J With this do I now compare the kinetic energy to the charge and this is the potential difference requirement? Like V=deltaKE/q=5.46627e-14/1.6e-19=3.42e5 V?

I'm sorry but I don't see how my equation doesn't take potential energy into consideration. I calculated the total energy of the electron at 0.8c and solved for the potential difference requirement by dividing by the charge on the electron. It is a little convoluted by me cancelling the charge...

Homework Statement An electron accelerated from rest through a potential difference V acquires a speed of 0.8c. Find the value of V. Homework Equations E=(gamma)mc^2, E=Vq The Attempt at a Solution For this I related the two equations above and chose a value of m=0.5MeV for the electron and...