Recent content by KurtWagner

That worked. Qwater = Qice + Qicewater

oh... It becomes water and has a different specific heat after 0∘C... hmmmm. Ill try that

Q = mi [(ci ΔTi) + Lf i] Would this equation not mean that each kilo of ice absorbs the heat needed to change its state and also to change its temp? for each kilo 2100 Joules per degree change in temp but also the 334kJ to change its state? Am i right in assuming that each kilo of ice changes...

I must be doing something wrong here but I cannot figure out what it is1. Homework Statement An insulated beaker with negligible mass contains a mass of 0.350kg of water at a temperature of 70.1∘C. How many kilograms of ice at a temperature of − 11.6∘C must be dropped in the water to make the...

Gravity is always accelerating the object. But the object has to stop before going backward (has to be 0 velocity). This is a really really really small time though.

Its also cool to note that even at the top of the motion, when the velocity is zero, the acceleration is still in the down (positive) direction.

... Assuming there is gravity

On the way up, your acceleration would be down (positive) and your velocity would be up (negative). Once the ball is falling, the acceleration is still down (positive) and the velocity is down (positive)

thanks. sorry for missing the units and for the typo also. I'll give it another crack. :)

So I have a boat going across a river (y-direction, north) 400m wide. I am trying to hit a target 75m in the positive x direction on the opposite side of the river. My boat will travel a velocity v. The river will provide a constant velocity of +0.5 (east) I am trying to find the angle a, north...

HA! Thank you. I did not realize. The square of the velocity! That is exactly what I was missing. 5^2 plus 5^2 is not the same as 10^2. Lol

so this brings me back to my misunderstanding involving the conservation of momentum. for example a moving car hitting a stationary one. initial car a: 1000kg 10m/s car b: 1000kg 0m/s final car a: ? car b: 5m/susing the conservation of momentum on this would leave car a going 5m/s right...

thanks for that :p

*cars

or should i say. most car collisions where the breaks are engaged in both cats