Optimizing Boat Angle for Hitting a Target Across a River

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SUMMARY

This discussion focuses on optimizing the angle of a boat to hit a target across a 400m wide river while accounting for a constant river velocity of +0.5 m/s. The user attempts to derive the angle α north of west using the equations of motion, but encounters issues with unit consistency and equation formulation. Key equations include the time taken to cross the river and the relationship between the boat's velocity components. The solution involves using trigonometric identities to resolve the angle accurately.

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KurtWagner
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So I have a boat going across a river (y-direction, north) 400m wide.
I am trying to hit a target 75m in the positive x direction on the opposite side of the river.
My boat will travel a velocity v.
The river will provide a constant velocity of +0.5 (east)

I am trying to find the angle a, north of west to point my boat.

hope that all makes sense.

so far I have:

y = vt or t = y/v
t = 400 / v*sin(a)

x = vt
75 = [0.5 - cos(a)] * t

then I plugged in t

75 = 200/[v*sin(a)] - [400*v*cos(a)]/[v*sin(a)]

I can't seem to solve this. Am I doing this the right way?

I was thinking I need another function and I remember having to use
sin(a)^2 + cos(b)^2 = 1
for something like this a while back. And if I do, how do I? Do I just solve the first two equations for sin and cos and then plug the equations into the third, expand them, then solve another for t and then plug it in and simplify?

any help would be greatly appreciated.
 
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Hello Kurt, sorry you missed the template. Please use it.

I wonder if your river velocity is 0.5 nautical miles per fortnight or 0.5 m/s, because you missed giving the units. With an error as a consequence:

If you had written your second relevant formula (under 2. in the template) as

75 m = [0.5 m/s - cos(a)] * t

you would have immediately seen that it is nonsense to add a cosine to a velocity (how long is a year plus one ?)

However, this appears to be a typo omission, because under "3. attempt at solution", the v pops up again.

A second error pops up if you temporarily assume the river not to flow. a can then be zero, but instead of t = 400 m / v you get a divergence. You want to interchange cos and sin.

For the rest, you're okay:
vt cos(a) = 400 m plugged into the second eqn gives you
$${75\over 400}v\cos\alpha = 0.5 - v \sin\alpha$$
which is a simple goniometric equation of the form ##a \cos\alpha + b\sin\alpha = c##.
The relevant expression to help you solve that is ##\sin(\alpha+\beta) = ...##
 
thanks. sorry for missing the units and for the typo also. I'll give it another crack. :)
 

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