Recent content by kvanr

You mean the diagonal symmetry? edit: Then that would make it equal 0 at the center? I was thinking it was zero?

Homework Statement Electric charge is distributed along each side of a square. Two adjacent sides have positive charge +Q on each, two sides have -Q on each. What are the x and y components of the net electric field at the center of the square? (Each side has length "a").Homework Equations...

:frown: I'm sorry I can't find it. It's because I'm stupid. edit: Long division.. hmm.. would it be the same as: -4x + 16x / (4-x^2) I checked and looks fine.. integrating now so final answer of -2z^2 - 8ln(4-z^2) Then just sub in root y for z^2

A/(2-x) + B/(2+x) = 4x^3/(4-x^2) A(2+x) + B(2-x) = 4x^3 (2A+2B) + x(A-B) = 4x^3 + 0x + 0 2A+2B = 0, so A=-B x(A-B)=0x, so A=B Therefore, no solution exists by the method I know.

Ah yes, interesting. So then I get it in the form 4z^3 dz / (4 - z^2) I see you can simplify the 4 - z^2 to: (2-z)(2+z), but then I tried to do partial fractions, and that also went nowhere, as there is no existing way to do a partial fraction for that that I could find? and again I am...

Yah, how? That's my question.

Just wondering if you can help me out, I have the following integral that I go to in some differential equation I came up with to figure something out here: Integrate: dy/(4-y^0.5) The root y screws me up.