Recent content by kylenic1997

I got 2.70m/s from (X-Xo)/t. With the info given I got (2.70m-0m)/1s. That gave me 2.70m/s. If that's not how I get the velocity, then I don't know how to. Those are the only formulas my professor has us use.

I thought that velocity= distance traveled/ time traveled. Since it traveled 2.70m/1s I figured it would be 2.70 m/s. From the example you gave me it seems like the last equation of my original post should be correct. For some reason it seems to make more sense that the first equation should be...

Homework Statement A boulder starts from rest and travels 2.70 m in the first second (from t = 0 s to t = 1 s). How far will it travel in the second second (from t = 1 s to t = 2 s)? Assume the acceleration of the boulder is constant. Homework Equations a=(V-Vo)/t X=Xo+at v^2-Vo^2=2a(X-Xo)...

I found the answer. Thanks for all your help!:smile:

Ok so the length of the known side is 12.5m. To find the other side I use 12.5msinθ which gives me 1.098275863m. Is this correct?

So the tension should be (.5)(52.0kg)(9.8m/s^2)sinθ, which equals 22.38725518. I'm unsure about the units since it would still be in Newtons and not meters. Am I missing a step to change it to meters?

So would the tension in this rope be found by multiplying 2900Nsinθ since that should give me the y value for the rope?

I was only using ma=∑F so far. Since it it is not accelerating i worked the equation into: 0=2Tsinθ-mg. Plugging in the information given it should be (52.0Kg)(9.8m/s^2)=2(2900N)sinθ. Which would make sinθ=.087862069, but I don't think this is correct since it doesn't have any units

I'm stuck on a homework question. It states, "Bob traverses a chasm by stringing a rope between a tree on one side of the chasm and a tree on the opposite side, 25 m away. Assume the rope can provide a tension force of up to 29 kN before breaking, and use a "safety factor" of 10 (that is, the...