Recent content by ladyrae

how about this one Using Differentiation solve a rocket is launched vertically and is tracked by a radar station located on the ground 12 kilometers from the launch site. When the rocket is 20 km away from the radar station, its distance from the station is increasing at the rate of 2500...

Use differentiation to solve the following A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at rate of 2 feet per second. How fast is the top moving down the wall when the base of ladder is 15 feet from the wall. What's the...

software Does anyone know a program available I can use to check my answers to problems like these...quotient rule, product rule, and chain rule. Thanks

maybe x(sec 5)(5tan 5)

How about d/dx (sec 5x) = (sec 5x)(tan 5x)(d/dx 5x) = (sec 5x)(tan 5x)(5) =(sec 5x)(5tan 5x) I am using the formula d/dx sec u = (sec u)(tan u)(d/dx u) Am I on the right track?

I am having trouble with part of a problem what is d/dx (sec 5x) is it ((sec 5x)(tan 5x)(d/dx 5x)) ? Or is 5 a constant multiple ? either way what next ? What would (sec5x)(tan 5x)(5) be? Thanks

sorry sorry for the repost..i didn't see page 2 Anyone?

last one Find the equation on the tangent line to the curve y = x^{3}-1 at the point (-1,-2) y ' = \frac {d}{dx}(x^{3}-1)=3x^{2} m= 3x^{2} = 3 (y-y_1) = m(x-x_1) -3x + y - 1 = 0 or y=3x+1 is this right?

last one Find the equation of the tangent line to the curve y = x^{3}-1 at the point (-1,-2) y ' = \frac {d}{dx}(x^{3}-1) = 3x^{2} m = 3x^{2} = 3 (y-y_1) = m(x-x_1) -3x+y-1 = 0 or y = 3x + 1

thanks Thanks..it should be \frac {-x^{6}-3x^{4}-6x^{2}-2}{(x^{4}-2)^{2}} can this be simplified?

2 left Use the quotient rule to find f ’(x) and simplify where possible Y = \frac{x^{3} + x} {x^{4}-2} Y ‘ = \frac {(x^{4}-2) (3x^{2}+1)-(x^{3}+x)(4x^{3})}{x^{4}-2} = \frac {-x^{6}-3x^{4}-6x^{2}-2}{x^{4}-2} Is this right? How about the last one? Anyone...Thanks

terrible typo...i was reviewing another problem like it wrote down the wrong equation... f (x) = (x+e^{x})(3-\sqrt{x}) f ‘ (x) = (x+e^{x})(-\frac{1}{2}x^{-\frac{1}{2}})+(3-x^{\frac{1}{2}})(1+e^{x}) =...

Thanks I'm doing a calculus assignment... Can anyone check the last one for me? Thanks

Thanks...the next one is the Product Rule Use the product rule to find f ‘ (x) and simplify where possible f (x) = (x+e^{x})(3-\sqrt{x}) f ‘ (x) = (x+e^{x})(-\frac{1}{2}x^{-\frac{1}{2}})+(3-x^{\frac{1}{2}})(1+e^{t}) =...

Thanks..can you check this one? Using the summation rule, find f ’(x) and simplify where possible: F (x) = \frac {x^{4}+2x^{2}-3x}{4\sqrt{x}} F ‘ (x) = (\frac{1}{4})(\frac{7}{2})x^{\frac {5}{2}}+ (\frac {1}{2})(\frac {3}{2})x^{\frac {1}{2}}-(\frac {3}{4})(\frac {1}{2})x^{-\frac{1}{2}}...