How Fast Does the Ladder Slide Down the Wall?

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A ladder leaning against a wall can be analyzed using the Pythagorean Theorem, where the relationship between the ladder's height on the wall, the distance from the wall, and the length of the ladder is expressed as x^2 + y^2 = z^2. By differentiating this equation, one can find the rate at which the top of the ladder is sliding down the wall (dy/dt) when the base is pulled away at a known rate. In a similar problem involving a rocket, the distance from a radar station can also be calculated using differentiation and the Pythagorean Theorem, requiring knowledge of the rates of change in both horizontal and vertical distances. Participants in the discussion emphasize the importance of showing prior attempts to solve these problems for better assistance. Understanding the relationships and rates of change is crucial for solving such related rates problems effectively.
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Use differentiation to solve the following

A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at rate of 2 feet per second. How fast is the top moving down the wall when the base of ladder is 15 feet from the wall.

What's the equation?

Thanks
 
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Use the Pythagorean Theorem.

x^2 + y^2 = z^2

Diffentiate:

x\frac{dx}{dt} + y \frac{dy}{dt} = z\frac{dz}{dt}

Solve for the desired variable, dy/dt in this case

\frac{dy}{dt} = \frac{z\frac{dz}{dt} - x\frac{dx}{dt}}{y}

Plug in values you know, using x^2 + y^2 = z^2 to determine distances you don't.

cookiemonster
 
how about this one

Using Differentiation solve

a rocket is launched vertically and is tracked by a radar station located on the ground 12 kilometers from the launch site. When the rocket is 20 km away from the radar station, its distance from the station is increasing at the rate of 2500 km/hr. What is the vertical speed of the rocket at this instant?

What is the equation?

Thanks
 
Same approach as the previous problem. Now you know x, y and can find z from Pyth. What is important is understanding what dx/dt and dy/dt are equal to.

Typically, we can help you only if you show us what you have tried and where you are stuck. We are not here to provide solutions to your homework.
 
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