Recent content by Lanc1988

Homework Statement A projection aligner has an object to lens distance of 500mm. Calculate lens diameter for the aligner if NA = 0.28. Assume the usable area of lens is 90% of its diameter.Homework Equations NA = r / D Note: NA is the numerical aperture. The Attempt at a Solution I know that...

i see now.. when i saw V=IR without thinking about it i just put the v for the velocity.. it all makes sense now, thanks for your help.

they told me to use the equation V=IR so the current should be equal to V/R.. how am i suppose to figure out what the current is then?

but they tell me in the walkthrough that all of those equations are correct.. at the end I am told that F = IwB and that I now have enough information to solve the equation for the final answer so I don't understand why it keeps telling me that my answer is wrong.

As i go through the walkthrough it tells me that 2 of the wires cancel each other out and I am only left with needing to calculate the force on the wire of length w

Homework Statement At t=0, a rectangular coil of resistance R = 2 ohms and dimensions w = 3 cm and L = 8 cm enters a region of constant magnetic field B = 1.6 T directed into the screen as shown. The length of the region containing the magnetic field is LB = 15 cm. The coil is observed to...

can anyone help me with this?.. i don't understand what Astronuc told me to try.. I've been trying to figure out this part for hours now..

anyone? I am sure I've got to be pretty close to the answer but I just must be doing one little thing wrong...

would you add the x's then? since its been stretched to 0.4m and then goes back to 0.2m so the x should be 0.6 in the equation i have?

still not quite sure what I am doing wrong.. the difference between them is still 0.2m.. am I using the wrong equation?

Homework Statement A spring is stretched a distance of Dx = 40 cm beyond its relaxed length. Attached to the end of the spring is an block of mass m = 11 kg, which rests on a horizontal frictionless surface. A force of magnitude 35 N is required to hold the block at this position. The force is...

ok.. got the answer right now. thanks for all your help! :)

im not sure what you mean by the mass is given in grams.. should it be converted to kg?

ok.. so the equations are: -T + µmg = m*R1*Theta^2 T + µmg = m*R2*Theta^2 so: -T + (0.77)(22)(9.81) = (22)(0.03)(13.8)^2 so T = 40.491 T + (0.77)(22)(9.81) = (22)(0.05)(13.8)^2 so T = 43.302 this is very confusing to me.. you said my equations are right so apparently i must be putting in a...

are the equations right then? when i solved for theta in the equations I did it by adding them together.. to solve for T would I solve the first one for T and then plug that value into the second one for T.. but if I do that then the T's go away which is what is confusing me...