So I did:
c/d^2 + c/d^2 =0
put in the numbers
(0.76*10^-6)/d^2 = (3*10^-6)/(d+13)^2
simplify taking out the fractions
(0.76*10^-6)(d+13)^2 = d^2(3*10^-6)
expand the bracket
(0.76*10^-6)(d^2+26d+169) = d^2(3*10^-6)
eventual rearrangement
2.24*10^-6 - 1.976*10^-5 -...
Homework Statement
Particle 1 of charge q1 = +0.76 µC and particle 2 of charge q2 = -3.0 µC, are held at separation L = 13 cm on an x axis. If particle 3 of unknown charge q3 is to be located such that the net electrostatic force on it from particles 1 and 2 is zero, what must be the x and...