Recent content by lanvin

cool, thanks for the help

wow I'm good (sarcasm) maybe i'll get this right before 2009 next attempt: vax/va = cos31 vax = 3.8 m/s vay/va = sin31 vay = -2.3 m/s vbx/vb = cos25 vbx = 7.1 m/s vby/vb = sin32 vby = 3.3 m/s ax = vbx - vax / t ax = 7.1 m/s - 3.8 m/s / 8.5s ax = 0.4 m/s(2) ay = vby - vbx / t ay = 3.3 m/s...

is this correct? Vx = 4.4sin31 + 7.8cos25 = 9.335 Vy = -4.4cos31 + 7.8cos25 = -0.4745 V^2 = 9.3^2 + (-0.47)^2 V = 9.3m/s

I don't think I understand. What do you mean? I wrote x where I was supposed to write y, and vice versa...??

oops! That was my mistake... the angle in the diagram should have read 25°. Is the answer fine otherwise?

A bird takes 8.5s to fly from position A to position B along the path in the figure shown. Determine the bird's average acceleration. http://i299.photobucket.com/albums/mm286/lanvin12/physics.jpg Vax = (4.4m/s)sin31° = 2.26616m/s Vbx = Vbsin25° = (7.8m/s)sin25° = 3.2964m/s Vx = Vbx - Vax =...

Mars travels around the sun in 1.88 {Earth} yrs,in an approximately circular orbit with a radius of 2.28 * 10^8km.Determine {a}The orbital speed of Mars {relative to the sun}Answer {a}: period {T} = 1.88 * 365 *24 * 3600 sec , R = 2.28 * 10^8 * 10^2 = 2.28 * 10^11 d = 2 pie R ------> 2 * 3.14 *...

A race-car driver is driving her car at a record-breaking speed of 225 km/h. The first turn on the course is banked at 15°, and the car's mass is 1450kg. 1. If the car maintains a circular track around the curve (does not move up or down the bank), what is the magnitude of the force of static...

wow thanks

alright, so F(s) = ma F(N) - F(g) = 0 F(N) = F(g) F(N) = mg F(s) = µ(s) F(N) ma = µ(s)mg a/g = µ(s) [2.5m/s²] / [9.8m/s²]= µ(s) therefore, the smallest coefficient of friction between the boxes that will prevent slippage is 2.6x10^(-1) something like that?

152N - F(f) 152N - (0.65)(22kg)(9.8N/kg) = 11.86N did I do it right?

Thanks for replying! Would I need to use a formula where the masses cancel? The only value the question gives us is the acceleration... which is 2.5m/s². Also the 9.8N/kg which is always assumed... ...I'm looking for µ, right?

Question is: "A box with a mass of 22kg is at rest on a ramp inclined at 45° to the horizontal. The coefficients of friction between the box and the ramp are µ(s) = 0.78 and µ(k) = 0.65 Determine the magnitude of the largest force that can be applied upward, parallel to the ramp, if the box...

Questions is... a small is resting on a larger box, which is resting on a table. When an applied force is applied to the larger box, the two boxes move together. The small box does not slip. If the acceleration of the pair of boxed has a magnitude of 2/5m/s^2, determine the smallest...

Homework Statement I just did this question, and I just want to make sure I did it right... Can u run through it and notify me of any errors? Homework Equations Here is the question: http://i299.photobucket.com/albums/mm286/lanvin12/333-1.jpg The Attempt at a Solution this is...