Using line equation y = -4058.7x + 16.10 with the experiment pressure measured in kPa instead of atm.
I already solved for heat of vaporization thus:
(-4058.7K)(-8.314 J/mol \astK)=heat of vaporization = 33444 J/mol = 33.44 kJ/mol.
Also, the vapor pressure for normal boiling point...