Recent content by ldbaseball16

i found the the kinetic energy its 752.5 and the melting point of the lead is 327 celsius and the specific heat is 130 kg c... i don't know how the kinetic energy plugs into this equation? I am using Q=mcT and to find Q i used this equation Q=mL, and then i pluged it into this one but i know its...

Homework Statement Ricky Plaxico Bobby grabs his .22 pistol and fires a 5.00g lead bullet into a block of wood. The muzzle Velocity 301 m/s. Assume that 50 % of the bullet turns to heat A.What is the temperature rise of the bullet? B. Will the bullet become hot enough to melt? C.If so...

ok, i got ln(4/sqrt(x^2 +16) + (x/4)? is this right?

Homework Statement (1/sqrt(x^2+16), x, 0, 4); Homework Equations x=4tan(theta) dx=4sec^2(theta)d(theta) The Attempt at a Solution (1/sqrt(16+(4tan(theta))^2)(4sec^2theta) I am confused can i get some help??

Tcos(145)+1.92cos(270)+12.1cos(180)+5.36cos(180)+5 7.6cos(270)+Fcos(21.3)=0 Tsin(145)+1.92sin(270)+12.1sin(180)+5.36sin(180)+5 7.6sin(270)+Fsin(21.3)=0 T+0-12.1-5.36+0+F.9316912276=0 T-1.92+0+0-57.6+F.3632512305=0 so it just stays as T and no <145>?

Tcos<145>+1.92cos<270>+12.1cos<180>+5.36cos<180>+5 7.6cos<270>+Fcos<21.3>=0 Tsin<145>+1.92sin<270>+12.1sin<180>+5.36sin<180>+5 7.6sin<270>+Fsin<21.3>=0 the <145> is the angle of the missing tension of the wire

Tcos(145)+1.92cos(270)+12.1cos(180)+5.36cos(180)+57.6cos(270)+Fcos(21.3)=0 Tsin(145)+1.92sin(270)+12.1sin(180)+5.36sin(180)+57.6sin(270)+Fsin(21.3)=0

i don't understand you mean like this ? <T<145>+<1.92<270>+<12.1<180>+<5.36<180>+<57.6<270>+<F<21.3>=0 and then convert to (x,y)?? right

ok Wnet=(1/2)mv^2-(1/2)mv^2 this is the work energy theorem but on the other equation i have to apply the kinetic friction to 45.2m? right and once i find the conservation of mechanical energy what do i do with that number? how do i apply it to the work-energy theorem?

Ricky Bobby?? Homework Statement Ricky Bobby jumps into his 1003kg pick up and heads out at 69.2mi/h. It's night and he notices too late the warning sign that the bridge is out. He slams on the brakes and skids for 45.2(kinetic friction=0.78)before hitting the long massive coil spring that...

oo thank you

Homework Statement solve by using intergration by parts x^2(cosx)dx Homework Equations My question is i got this answer but my computer algebra system gave me this answer (x^2-2)sin(x)+2xcos(x) can you tell me where i went wrong?? The Attempt at a Solution u=X^2 dv=cosx du=dx...

ln5*sinh(x)+ln5*x*cosh(x)?

1/5xcoshx

i used the chain rule and i got e^(ln5xsinhx)(ln5)??