Recent content by ldixon

  1. L

    Identifying Unknown Solutions in Chem Lab: NH3 + CuSO4 and NaI + CuSO4 Reactions

    Where did you get the OH- from? So the neither one of these reactions should be a percipitate?
  2. L

    Identifying Unknown Solutions in Chem Lab: NH3 + CuSO4 and NaI + CuSO4 Reactions

    Deep blue percipitate NH3 (aq) + CuSO4 (aq) -------> Cu(NH3)4SO4 (s) Should there be a + between the Cu(NH3)4 and SO4? brown heavy percipitate 4NaI (aq) + 2CuSO4 (aq) -------> 2CuI (s) + I2 (s) + 2Na2SO4 (aq) Is the I2 solid or aqueous? What gives the brown color?
  3. L

    Identifying Unknown Solutions in Chem Lab: NH3 + CuSO4 and NaI + CuSO4 Reactions

    Chem Lab "ID of Unknowns" I had to find 5 unknown solutions in a recent chem lab and now I am doing the equations, but I am not sure about two of them: Deep blue percipitate NH3 (aq) + CuSO4 (aq) -------> Cu(NH3)4 SO4 (s) brown heavy percipitate 4NaI (aq) + 2CuSO4 (aq) -------> 2CuI (s)...
  4. L

    Solubility and Net Ionic Equations for Chlorides and Iodides

    Actually according to my chemistry professor My answer was correct, becasue the Cl2(g) is not aqueous so the chloides do not cancel out. Thanks Borek for the correct answer.
  5. L

    Solubility and Net Ionic Equations for Chlorides and Iodides

    Please someone can you clairify this problem for me? I don't think Stevedye56 is correct on this?
  6. L

    Solubility and Net Ionic Equations for Chlorides and Iodides

    Ok here is the problem: 2NaI (aq) + Cl2 (g) ----- 2NaCl (aq) + I2 (s) For the net ionic I got: 2I- (aq) + Cl2 (g) ------- 2Cl- (aq) + I2 (s) Is this correct? Most chlorides and iodides are soluble, but one states (g) and the other states (s) so does that mean they are not...
  7. L

    What Is the Mystery Acid in Test Tube #3?

    Ok I think it would be HNO3 because it is always soluble with no exceptions, so there would be no visual reaction? Does that sound legit?
  8. L

    What Is the Mystery Acid in Test Tube #3?

    yes low PH means a low number, the problem is written just like that. I can not figure anything out for it.
  9. L

    What Is the Mystery Acid in Test Tube #3?

    Yes acids contain H+ and bases contain OH, and yes I think there is a list of salts in the book.
  10. L

    What Is the Mystery Acid in Test Tube #3?

    Im not sure what you mean, I don't know what the acid is that has no reaction with all 8 of the listed reactants?
  11. L

    What Is the Mystery Acid in Test Tube #3?

    I have a question on a pre-lab that I have to do. The question is: You determine that test tube number 3 is an acid. It is colorless, odorless and has a very low pH value. You test the sample with all eight(8) reactants available and find no reaction(NR). What is the acid? Explain your...
  12. L

    Pre-Lab Question: Identifying Acid with No Reaction to 8 Reactants

    I have a question on a pre-lab that I have to do. The question is: You determine that test tube number 3 is an acid. It is colorless, odorless and has a very low pH value. You test the sample with all eight(8) reactants available and find no reaction(NR). What is the acid? Explain your...
  13. L

    Understanding Chemistry Lab Formulas: MgO, Mg(OH)2, and H2CO3 Explained"

    We lit a piece of Mg so the formula is: 2Mg(s) + O2(g) HEAT-- 2MgO(s) We then dissolved this in water so it would then be: MgO(s) + H2O(l) -- Mg(OH)2(l) Next we blew into water which is: CO2(g) + H2O(l) -- H2CO3(l) Is this all correct? Should I have (Aq) after the H2CO3?
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    Is My Calculation of NO2 Produced from N2O5 Decomposition Correct?

    2N2O5 heat-- 4NO2 + O2 1.618 g of O2 are produced, how much NO2 in grams are produced? I got 9.30 g NO2, is that right? I used 1 mol O2 = 32 g O2, and 1 mol NO2 = 46g NO2. I first converted g O2 to Mol O2 then used the balanced equation to convert from mol O2 to mol NO2, then converted to NO2...
  15. L

    Understanding Chemical Reactions: From Mg and O2 to CO2 and H2CO3

    We lit a piece of Mg so the formula is: 2Mg(s) + O2(g) HEAT-- 2MgO(s) We then dissolved this in water so it would then be: MgO(s) + H2O(l) -- Mg(OH)2(l) Next we blew into the solution which made it: CO2(g) + H2O(l) -- H2CO3(l) Is this all correct? Should I have (Aq) after the...
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