Recent content by leena19

OK.thx. Now for Q2) went through pages and pages of text and finally realized r= (a+b-c)/2 and r=radius of circle=2 As suggested,tried using the pythagorean triples and I end up with an area of 24 ? I really hope this is correct. I'm still having problems with Q3) For the...

thx for replying snipez90. I'm a bit too tired right now to really concentrate. I'll try to work this out tomorrow and if I still have a problem ,I'll post. Thank you all.

Thanks for the quick response,Mark44 and Elucidus! Yeah,that makes more sense.thx. Now I'm having a bit of trouble with Q3) and Q5) I understand there are three triangles ,but I'm not sure how i could find the area for the 3rd triangle,"where no corners share an edge" ? For Q5) I'm a bit...

Basic math problems(not homework & not urgent,but would like help anyway) Let me start by saying,I don't do math for my A/Ls(instead I chose bio )and I haven't done any math for a very long loooong time,but I've always loved math. I have some time off,so I got this set of miscellaneous...

I've looked at a few websites and some say it is slightly soluble,some say it is insoluble in water and others say it is soluble only in hot water. I'm not sure which one is true. Hope someone can help. Thank you.

Thanks for the very useful link. Ok so the oxidation state of Bi in BiH3 is +3 and in BiH2-,it is +1 . Then,since it's a metal it has to be more basic(i.e less acidic) than SbH3. But SbH3 and AsH3 are metalloids...? Can you tell me what I should do next? thx.

All group 5 hydrides are trivalent,so the oxidation state of Bi would be -3 The same. -3 ? Not sure how to proceed from here.

THANK YOU VERY MUCH FOR REPLYING! Er...is that a trick question ? Sorry if my problem isn't clear,but this is basically what my question is, \stackrel{\leftarrow}{} Arranged in increasing order of acid strength AsH3 > PH3 > NH3 > SbH3 > BiH3 The acidity increases from NH3 to AsH3,then the...

Hello everyone, this is a question I've asked at another chemistry forum, and has been bothering me for awhile . http://www.chemicalforums.com/index.php?topic=34742.0" And ... the only only reason I'm posting it here aswell,is causeI have my chem exam on Thursday(the day after tomorrow)...

Yeah.The rest are easy. Thanks for the help,sir. You're awesome!

Oh that's the conservation of momentum equation.i feel so stupid i completely missed it. Anyway,this is what i get \downarrow m1v1 - m2v2 = 0 50 * v1 = 25*v2 v2 = 2v1 Then, 2v1 = 0.5 - v1 3v1=0.5 v1= 1/6 Is this correct now? THANK YOU!

OK,I'm kinda desperate here.I have a physics exam the day after tomorrow and i have a lot more to revise,but I can't seem to concentrate in my studies without solving this problem,so anybody know how i could find expressions for VCM? Thanx

Well,if that's the case,I'm sorry I don't know to write an expression for VCM. One more hint,please...?

Is VCM the velocity of center of mass? Here's the pic. anyway http://img441.imageshack.us/img441/3106/balloon.png"

The balloon doesn't seem to be moving in the picture,but its just a rough sketch that our teacher put up on the board for us to copy. I could draw the pic, if needed.may take a few minutes