Recent content by LegendF

I see, I see. The issue is that the magnetic flux does infact change if I think about it, however it's nowhere mentioned that that it has anything to do with magnetic flux nor that the flux actually changes in the examples provided in my book. It just states that Lenz Law is that a force is...

Weird, that's not mentioned anywhere in my book and it has not been used in the examples either. So Lenz Law should only be applied when the magnetic flux changes? But can I still use "my method" even if the flux changes?

Ok, I'm with you on all points however there's just a final thing I'm a bit unsure of. If we're only looking at the magnitude of the displacement, then in our formula; F = -ky, why do we pay attention to the displacement when we're going below our equibrilium, for example if we go 3 units below...

This is an image of what I ment; http://s27.postimg.org/z5uaeoww3/thisedit.png I mean that when the spring goes downwards, but it's actually still above the equibrilium point, is the displacement then -S3, if we name the displacenment S3? And is the sign then - if we wish to take the...

I'm not sure what you mean by 'zero-level'. Do you mean the equilibrium point, where the net force on the mass is zero? -- Yes exactly. I'll re-write my question a bit perhaps was a bit unclear. So you mean that if the spring displaces anywhere downwards, the signed displacement is y =...

Ok, so if I understood you correctly. Because we know the direction of the forces, we take the absolute value of the displacements s0 and s1, because Fspring = k * (Displacement), and we already know which direction the force is going into, so it's to no interest to us to take the signed...

I'm with you on all points except the first one, Al. Mg is drawn downwards, Ks0 is drawn upwards. But! If s0 is + or - direction, I can't see where that's mentioned. Because if I would of defined positive direction upwards, and at b) We can see that the spring has a downward displacement. Would...

Hm. So let's say if I wanted to calculate the direction of the vectors(forces), would I then pay attention to the direction of the s0 and s1? If not then, when would I think like I was trying to do in my original post? For example if I've the equation on its final form: F = -ky. If I then...

Hmm.. So I would do like I was trying to, (like in my original post, and think in the way like I did in the second post of mine..) if I wanted to figure out the directions of the forces or..? :s Because if I understood you correctly the book has simply assumed that mg goes downwards, ks goes...

I do know this, but I'm trying to understand how they have explained the equation, which I obviously can't understand for some reason! :(

.. I can't understand why they are positive in that case. I assume. For example, always when I've calculated I've thought of it as negative in another chapter (Movement in 2D) Which is driving me insane.. If I have a water-level that is defined as my zero-point and I stand 20m above, at a...

Homework Statement Hello there! I'm having a big issue with understanding my books explanation. The image is taken from my book. The book is trying to prove the formula F = -k*y. This is the chapter ( Simple Harmonic motion) They got the following equations(Explanation from book): ---...

Important: Imagine that there is a wire connecting the two magnetic poles, (+,-) so there is an induced current and not only an ems. Homework Statement Hello there! I'm wondering if I can use both of these methods to calculate the direction of the current. The first one is Lenz...

I see, very good explanation. It's all about a matter of reference then, where you place the object and then just make sure that the forces/vectors point out the same way based on the plane the object is on. If a force is going out of the board, then it's going out of the paper, both forces...

So if I get a problem to solve, (determine the direction of the magnetic field), on my paper and if I imagined it being wrote on the board I would not get the same result as I would by determing the magnetic field by looking at my paper, but I would get the same result with respect to the frame...