Recent content by Leitmotif
-
L
Showing that spectrum of operator is not compact
Point taken. Thanks for the input :)- Leitmotif
- Post #6
- Forum: Calculus and Beyond Homework Help
-
L
Showing that spectrum of operator is not compact
Well, I guess I came up with an example of a function that's in the domain, and whose set of eigenvalues are not bounded, and eigenvalues are in the spectrum. I just wasn't really sure if that is enough to show that it's true for ALL functions in the domain. Also, I noticed I made a mistake...- Leitmotif
- Post #4
- Forum: Calculus and Beyond Homework Help
-
L
Showing that spectrum of operator is not compact
Yikes, the preview looked fine, but not sure what happened with that LaTeX code there. The operator is second derivative, Tx=x", and the domain is all functions in X so that x(0)=x(Pi)=0.- Leitmotif
- Post #2
- Forum: Calculus and Beyond Homework Help
-
L
Showing that spectrum of operator is not compact
Homework Statement Let X=C[0,\pi]. Define T:\mathcal{D}(T) \to X, Tx = x" where \mathcal{D}(T) = \{ x \in X | x(0)=x(\pi)=0 \}. Show that \sigma(T) is not compact. Homework Equations None. The Attempt at a Solution Well, functions sin(Ax) and sin(-Ax), for A=0,1,2,... are in the domain...- Leitmotif
- Thread
- Compact Operator Spectrum
- Replies: 5
- Forum: Calculus and Beyond Homework Help