Recent content by leo255

I'm happy to say I'm currently untying my tie, and winding down at home...I passed. The presentation could not have gone better.

Hello, just thought I'd bump this thread...Anyway, my thesis was finally given the "go ahead" a few days ago by my chair. Putting together my powerpoint slides and am trying to get ready for a defense in about a week. I'll probably be pretty nervous for it.

Yes, delayed. To be honest, my chair is not a native English speaker and it can sometimes be hard to understand him. The explanation that he gave wasn't clear. I will need to visit with him many more times to make sure I know exactly what he wants.

Well, I'm bummed! Masters in Computer Science student here...At the start of this semester, I was about 99% sure I was going to graduate this semester. The thesis/project that I did/am doing is a mobile app including some testing/benchmarks, but I also did a ton of research/lit review...

I agree! Excellent advice, thank you guys. The only thing...Please tell me this is NOT what I'm going to be looking forward to in the real world. This is my last semester and I was hoping that I was going to be done with this problem. I would assume at most companies, if you are not competent...

I am a Computer Science major - I am unfortunately in a group where the other two members are lazy, and I end up doing most of the work. It's too late to change groups. The class itself consists of a research paper/presentations, as well as a programming project/app. Every time I clearly tell...

Very helpful, thanks guys!

Thanks for the reply, I was just expanding out the k+1, so I could say definitively that the expression being multiplied by 2 in the hypothesis is larger 11(k + 1) + 17

Homework Statement Prove by mathematical induction: 2^n >= 11n + 17, for n >= 7, and n is an integer. Homework EquationsThe Attempt at a Solution This is my attempt - I want to see if I'm doing this correctly. 2^n >= 11n + 17, n >= 7 basis 2^7 >= 77 + 17 128 >= 94. True. Induction...

Homework Statement [/B] floor((n+1)/2) Find whether this function is 1-to-1 and/or onto from Z to Z. Homework EquationsThe Attempt at a Solution This is not one-to-one because f(1) = f(2) = 1. Regarding onto, we need to show that f(a) = b floor((n+1)/2) = b 2b = n + 1 n = 2b - 1 f(2b-1) =...

@haruspex, thanks for cleaning up my numbering/lettering. Yeah, my mistake - I meant b and c of #1 are 10^8. Regarding 2 C, I think I see what is being asked. There are 7 different places the 3 could appear, and then after that, the rest of the 6 spots have nine available choices for numbers...

Find the number of subsets of S = {1,2,3,...,10} that contain (a) the number 5. (b) neither 5 nor 6. (c) both 5 and 6. (d) no odd numbers. e) exactly three elements. (f) exactly three elements, all of them even. (g) exactly five elements, including 3 or 4 but not both. (h) exactly five...

Sorry for not making all of that clear. Again, thanks guys for your help!

Thanks! I think I got it. I was really getting confused by the '4,' but see that those are the only possibilities (i.e. 1,2; 2,3; 3, 4; 4, 5) - the fifth option would be 5, 6, and that would not exist in this context. The 2, as you said, is just where they happen to be positioned.

Ok, so answering my own question, I now see where the 2 comes from for e. We need to account for the possibility of one out of the two being in the picture. Still working on f.