Ok, I made a diagram to bring some clarity to the confusing mumbo jumbo I have written :P
Like I stated earlier my confusion lies within the fact that you can use x as the height in the equation Ep. Why is this viable? I thought you needed the height of the object ABOVE the ground.
So why...
I solved the question already during the test, and got it correct.
I just wanted to know the reasoning behind why Ep is still usable in a direction against gravity. I thought the whole reasoning behind Ep was that when an object is lifted from the ground upwards, it's potential energy is...
The length in the stretch of the spring is represented by x. And x can also be used as h.
Ee=(k*x2)/2
Ep=m*g*h
After substituting all the values, k can be solved for.Edit: that is correct, 6stang7.
I can. I just really wanted to know why it is that you can use Ep to solve a question like this.
I also asked my teacher this question after the test, and she told me as well it's all relative. But then I asked her why you can use gravity? Especially if the acceleration of gravity is in the...
Hello everyone!
To start things off, I apologize if this thread does not go here.
Today I had a test on Energy (Potential, Kinetic, Elastic) and we had a question which asked us to find out the value of k for a spring. The question was centered around a box hanging from a ceiling via a spring...
Hello forum, today in my gr. 12 physics class I had a interesting question which I could not prove at all for the life of me. It is a really simple question, just with a little twist I suppose. As I was driving home from class I was thinking about what I was missing and thought up a solution...