- #1
LeonGrande
- 8
- 0
Hello forum, today in my gr. 12 physics class I had a interesting question which I could not prove at all for the life of me. It is a really simple question, just with a little twist I suppose. As I was driving home from class I was thinking about what I was missing and thought up a solution. Anyways I'll state the question and all that jazz...
1. Two people are sitting in a canoe which sits in the middle of a lake. Both individuals have a mass of 75kg, and the canoe itself has a mass of 50kg. The canoe is not moving, nor are the people sitting inside. Person 1 decides to throw to Person 2 a life jacket (edit: life jacket has a mass of 1kg) at 10m/s [E].
Calculate the theoretical velocity of the canoe while the life jacket is still in mid air.
Also,
Calculate the velocity of the canoe after person 2 catches the life jacket.
Side note... the question was not worded at all like this, it was much more confusing! lol
m1*v1o+m2*v2o=m1*v1f+m2*v2f
v=velocity
m=mass
o=initial, f=final
So here is my attempt at a solution,
(a) (1kg)*(0m/s)+(200kg)*(0m/s)=(1kg)*(10m/s)+(200kg)*(X)
X= -0.05m/s
(b) (1kg)*(10m/s)+(200kg)*(-0.05m/s)=(1kg)*(0m/s)+(200kg)*(X)
X= 0m/s
...So there it is. I was not to sure whether or not I should have combined the masses or not.
Sorry for any typos, I just got home and am drained. Thanks for any help!
1. Two people are sitting in a canoe which sits in the middle of a lake. Both individuals have a mass of 75kg, and the canoe itself has a mass of 50kg. The canoe is not moving, nor are the people sitting inside. Person 1 decides to throw to Person 2 a life jacket (edit: life jacket has a mass of 1kg) at 10m/s [E].
Calculate the theoretical velocity of the canoe while the life jacket is still in mid air.
Also,
Calculate the velocity of the canoe after person 2 catches the life jacket.
Side note... the question was not worded at all like this, it was much more confusing! lol
Homework Equations
m1*v1o+m2*v2o=m1*v1f+m2*v2f
v=velocity
m=mass
o=initial, f=final
The Attempt at a Solution
So here is my attempt at a solution,
(a) (1kg)*(0m/s)+(200kg)*(0m/s)=(1kg)*(10m/s)+(200kg)*(X)
X= -0.05m/s
(b) (1kg)*(10m/s)+(200kg)*(-0.05m/s)=(1kg)*(0m/s)+(200kg)*(X)
X= 0m/s
...So there it is. I was not to sure whether or not I should have combined the masses or not.
Sorry for any typos, I just got home and am drained. Thanks for any help!
Last edited: