We take the average of cells with A only: x1 + x2 + x3 / 3
Then we take the average of cells with A + B: x4 + x5 + x6 / 3
So the ratio A+B / A = (x4 + x5 + x6) / (x1 + x2 + x3)
1 - (x4 + x5 + x6) / (x1 + x2 + x3) = the reduction in proliferation.Yes, G's are generations.
G1 is the parent...
Let me give you an example data set.
Cell A only
G1 (parent): 8.89%
G2: 8.47%
G3: 14.94%
G4: 23.85%
G5: 24.27%
G6: 15.66%
G7: 4.12%
The proliferation index (average number of divisions) is calculated as sum i*Gi / 100% = 4.57. So if we started with 1 million cells, the final population is...
Instead of "therefore", take it as "In summary,"
Let me help clarify the rest:
I am measuring proliferation as the average number of times that the cells divide. We track cell division by labeling the cells with a dye called CFSE. Parent cells will have 100% CFSE levels, 1st generation 50%...
Thanks for your replies!
To clarify (please excuse my sloppy notation):
This is true. However, I do not think X-Y is normal. After doing some more searching on google, X and Y are Cauchy distributions. I was wondering if there was a test (along the lines of t-test or F-test) for this...
Hi everyone!
I have a question on how to compare two distributions. I'm currently a 2nd year biology grad student, and I'm trying to compare a parameter that evaluates the efficacy of a cell type. The math problem is this:
Let X and Y each be an average of three variables divided by an average...
Solved... i think. It's just Psi(x) = B sin kx
Homework Statement
Consider a free particle psi(x) = A*e^(ikx) approaching an infinite barrier from the left:
V = 0, x < 0 and V = oo, x >= 0. For this problem use only the time-independent
Schrodinger Equation.
a. Find the probability of being...