Recent content by letsgo

So here are two wires. With currents in the specified direction. What I want to know, is how do you determine the direction of the magnetic moment of the upper wire, which would ultimately lead to me determining what direction its torque is in, therefore letting me determine what direction it...

So let's say I have a current, going into the page (that is, -\hat{k}). And now let's say you're trying to figure out the magnitude and direction of the magnetic field 0.0346 m away from it, in the SW direction (45 degrees). How would you calculate the answer in terms of unit vectors \hat{i}...

Okay, is it 90? So then it means it is circular? Since even though its 30 degrees from the x-axis, its still perpendicular to the B-field?

There's basically a beam of protons moving in the x-y plane, 30 degree from the +x-axis. The magnetic field is oriented in the +z-axis. So would the particle's motion be circular or helical? I say helical, because the velocity isn't completely perpendicular. Is this correct?

Okay, I got the correct answer for EMF, but now I can't get b). I treated I1 as the 1 A current, and I3 is therefore 1.14 A. It works out, because I plugged in those values to get EMF. So then I2, which is equal to I3-I1 gives me 0.14 A, but the answer given is 0.929 A. PS. My version of...

I finally get it. :eek: Thank you! So this method of replacing the battery with a wire and remaking the circuit (the image you supplied me with), is this what finding the Thevinin equivalent is (I haven't learned this yet), and is this something that you have to do to solve this problem?

Okay, 66.7 ohms, my bad. But no, I still don't see it. Because the way I see it, is if you're not considering the capacitor, then the resistors ARE in series. Because the current goes from the source to 200 to 100. There is no junction. See but this is when the circuit is in a steady state...

Okay, so its 75 ohms, because you treated them as parallel. But why did you treat them as parallel?

Can you PLEASE just answer the question... Is it 100 ohms or 300 ohms...? PLEASE.

Thanks. And OK, you're right, I fixed it. V=Q/Ceq 4.68=Q/21.8mF Q=1.02 C, which is the same across each capacitor since they're in series. And can you please, since you seem to know what you're talking about when it comes to RC circuits, answer this question of mine as well...

Smart, thanks.

Homework Statement If you have this RC Circuit (ignore the yellow path of current): http://i.imgur.com/Mi2bj.png When you are calculating time constant=RC, what would you use for R? R1=100 ohms, or Req=300 ohms Homework Equations time constant = RC The Attempt at a Solution...

So are the other answers good to?

Homework Statement Consider the circuit below, where C1=80mF, C2=30mF, R=50ohms and E=5V. At t=0, both capacitors are uncharged - so it's charging. The circuit is in series, with E ---> C1 ---> C2 ---> R ---> (back to) E a) Find the time constant. b) The initial potential...

So when I apply the loop rule, how does the "ground" change it? I still don't get it...