Recent content by lindz.12

thank you!

Consider a pair of binary stars with a separation of 3.60E12 m and an orbital period of 2.55E9s. Assuming the two stars are equally massive, determine the mass of each. keplar's law... so I rearranged the formula and set (2pi*r)/T=sqrt((GM)/r), and then I solved for M, which gave me the...

thanks.

thank you...but where did you get 399,000? isn't GM 3.98E14?? and also, I'm confused on why the radius is 2 and 3.5...?

the distances are what i know... earth's mass is 5.97E24...whereas its radius is 6378 km... the answer i got in km/s was 249866.38...which is wrong..and idk why.

Compare the orbital speeds of satellites that orbit at the following altitudes. (a) One Earth radius above the surface of the Earth (in km/s) (b) Two and a half Earth radii above the surface of the Earth. Here is the equation to be used, orbital speed is v=(sqrt)(GM/r) G is the...