Consider a pair of binary stars with a separation of 3.60E12 m and an orbital period of 2.55E9s. Assuming the two stars are equally massive, determine the mass of each.
keplar's law...
so I rearranged the formula and set (2pi*r)/T=sqrt((GM)/r), and then I solved for M, which gave me the...
the distances are what i know...
earth's mass is 5.97E24...whereas its radius is 6378 km...
the answer i got in km/s was 249866.38...which is wrong..and idk why.
Compare the orbital speeds of satellites that orbit at the following altitudes.
(a) One Earth radius above the surface of the Earth (in km/s)
(b) Two and a half Earth radii above the surface of the Earth.
Here is the equation to be used,
orbital speed is v=(sqrt)(GM/r)
G is the...