Recent content by livewire5

but what if you have an infinite charged plane or a disk of charge it would be aligned up in x-y axis and your z axis would be the r and surely the Radius R would just mean the distance z is which isn't inside that charged plane...what you are saying works for sphere of charge or other 3d...

http://img94.imageshack.us/img94/4392/ppcapqs2.png http://img267.imageshack.us/img267/5059/ppcapqs1.png In this question the charge is calculated by isolating Q in E=surface charge density/absalon not My question is, the electric field of an infinite charged plane is E=surface charge...

I am not sure why or how the distance away from a charged conductor, r, is greater than the radius of that charged conductor or surface, R, then the electric field is that of a point charge.. if r>>R then we are far from conductor. if r<<R then we are close to the conductor.. these are...

got it! its because my numerator is dy and the constant next to it is d not "y" so I can't use the 2nd integral.

thats what I am wondering, how do you know which integral to take because 1 and 2 are both very similar and 2 matches more closely to my equation so any ideas on why I should be taking integral 1?

Im so confused why is the integral the first one rather than the 2nd one? If I turned my difference in L to difference in y which becomes dy then d*dy is what numerator would be and 2nd integral looks closer match for it than the 1st integral.

I am not sure whether this is the correct section to post in but here it goes... I am really confused as to why the textbook has a "d" in denominator and why their integral is different from mine...I used the integral in 2nd column 2nd row but the textbook is different :S I am not sure why...